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anygoal [31]
2 years ago
6

The sum of two positive integers is 18 and their difference is 2. What is the larger number?​

Mathematics
1 answer:
choli [55]2 years ago
5 0

Answer:

10

Step-by-step explanation:

we call the numbers x and y

then from the given data:

x+y=18

x-y=2

we add both sides of both equations

x+y+x-y=20

2x=20

x=10

we use the first equation:

10+y=18

then y=8

the larger number is x=10

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Step-by-step explanation:

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Quick please no links or anything just the straight up answer answer both please
Serjik [45]
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4 0
2 years ago
3/9 + 3/27 = ? Adding fractions
RideAnS [48]
\frac{3}{9} + \frac{3}{27} equals \frac{4}{9}.

First, simplify \frac{3}{9} to \frac{1}{3} and also \frac{3}{27} to \frac{1}{9}. Your problem should look like: \frac{1}{3} + \frac{1}{9}.
Second, find the least common denominator of \frac{1}{3} and \frac{1}{9} to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like: \frac{1x3}{3x3} + \frac{1}{9}.
Fourth, simplify to get the denominators the same. Your problem should look like: \frac{3}{9} + \frac{1}{9}.
Fifth, join the denominators. Your problem should look like: \frac{3+1}{9}.
Sixth, simplify. Your problem should look like: \frac{4}{9}, which is the answer.

4 0
3 years ago
DBE is obtained by enlarging ABC. If the area of ABC is 3 square units, what is the area of DBE?
Amanda [17]

Answer:

The area of DBE = 27 square units

Step-by-step explanation:

Area of ABC = 3 square units

In the figure, we can see that ABC was enlarged so that BDE is formed where side BD = 6 and AB was = 2

Hence ABC was enlarged 3 times its size.

We know by formula that:

Area of ABC = 1/2(base x perpendicular)

3 = 1/2(2 x p)

=> p = 3

As ABC was enlarged 3 times its size, the perpendicular of BDE must be 3*p

= 3*3 = 9

AREA OF DBE = 1/2(base*perp)

= 1/2(6*9)

= 27 square units

8 0
3 years ago
Can someone help me pls
BartSMP [9]

Answer:

30.4

Step-by-step explanation:

if you want the basic perimeter just add up all the sides

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3 years ago
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