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Alex Ar [27]
3 years ago
5

Solve the equation using distributive property and properties of equality

Mathematics
1 answer:
netineya [11]3 years ago
8 0

Answer: -5(8+3) = -55

Step-by-step explanation: a = 8

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How do you solve this math problem of ratio?
Alex17521 [72]
I don't know, this is tricky
8 0
3 years ago
Every week, Hector’s 20 hours earns $210.00. He earns a constant amount of money per hour.
lesantik [10]

Answer: 20 weeks in 1 week

in 2 weeks 40

Step-by-step explanation:

This proves that the equation is true

3 0
3 years ago
Help now pls! Algebra 1 HW stuck on a question
Rus_ich [418]

Answer:

false a = -3

Step-by-step explanation:

7v^2 + 2v^3 -7v - (5v^3 -4v^2 +10v)

7v^2 + 2v^3 -7v - 5v^3 +4v^2 -10v

-3v^3 + 11v^2 -17v

6 0
3 years ago
A jewelry box is b2 inches long, 3c2 inches wide, and 2c1 inches tall. Which of the following are correct? Select ALL that apply
Mariulka [41]

9514 1404 393

Answer:

  B, F

Step-by-step explanation:

The volume is the product of the dimensions:

  V = LWH

  V = (b^2)(3c^2)(2c^1) = (3·2)(b^2)(c^(2+1))

  V = 6b^2·c^3 . . . . . matches B

__

For b=3 and c=2, the volume is ...

  V = 6(3^2)(2^3) = 6(9)(8)

  V = 432 . . . . cubic inches . . . . matches F

6 0
3 years ago
The box plots below show the distribution of salaries, in thousands, among employees of two small companies.
Shtirlitz [24]

Answer:

Mean and IQR

Step-by-step explanation:

The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.

For company A:

Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.

Hence, the mean will be the best measure of centre rather Than the median in this case.

For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.

7 0
3 years ago
Read 2 more answers
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