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bija089 [108]
3 years ago
12

Kim uses decals to decorate 5 cars and 2 motorbikes. She uses 2/3 of the decals on the cars and 2/5 of the remaining decals on t

he motorbike. she has 6 decals left. How many decals does Kim use on each car?
Mathematics
1 answer:
ladessa [460]3 years ago
6 0
Let the number of decals be D. After using decals on the cars she has D-2D/3=D/3 left and after using decals on the bikes she has (1-2/5)D/3=(3/5)D/3=D/5 decals left. So D/5=6 and D=30.
2/3 of D=20 so she uses 20 decals on 5 cars (4 decals for each car). 2/5 of the remaining 10 decals=4 which uses on the bikes (2 on each bike).
Let’s see if it all adds up: 20 + 4 + 6 = 30. OK. 20 is 2/3 of 30. OK. 2/5 of 10 is 4. OK.
And 20 decals shared by 5 cars is 4 per car.
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Distributive property pls helpp
GaryK [48]

9514 1404 393

Answer:

  • 4
  • 16

Step-by-step explanation:

If you consider matched parentheses to identify the contents of a "bag", the multiplier outside parentheses tells you how many bags you have. When you use the distributive property, you effectively dump all those bags on the table.

Here, the expression 4(6v +4) tells you there are 4 bags and each one contains 6v and 4. When you open them all up, you have ...

  4(6v +4) = 6v +6v +6v +6v +4 +4 +4 +4

Of course, we can use multiplication to simplify repeated addition, so we can also write this as ...

  4(6v +4) = 4·6v +4·4 = 24v +16

The numbers that go in your boxes are identified by their bold font style.

5 0
2 years ago
Choose all of the equations that are equivalent to 8k = 20
Orlov [11]
It’s definitely is A,D, and C
8 0
2 years ago
Read 2 more answers
Here is a simple probability model for multiple-choice tests. Suppose that each student has probability p of correctly answering
Alla [95]

Answer:

a) The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

Step-by-step explanation:

a) To approximate this distribution we have to calculate the mean and the standard distribution.

The mean is the proportion p=0.85.

The standard deviation can be calculates as:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{100} }=0.04

To calculate the probability that Jodi scores 78% or less on a 100-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.04} =-1.75

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) In this case, the number of questions is 250, so the standard deviation needs to be calculated again:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{250} }=0.02

To calculate the probability that Jodi scores 78% or less on a 250-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.02} =-3.5

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

6 0
2 years ago
Dingane has \$8.00$8.00dollar sign, 8, point, 00, and exactly 30\%30%30, percent of that money is from 555‑cent coins. How many
Ipatiy [6.2K]
<span>If Dingane has $8.00, and thirty percent of that money is from five cent coins, then 8 x 0.3 = $2.40 of Dingane's money is made of five cent coins. In this case the number of five cent coins is the number of cents divided by five: 240/5 = 48. Therefore, Dingane has forty-eight five-cent coins.</span>
6 0
3 years ago
Anyone got answers to this? Need help asap it’s due tomorrow!!
umka2103 [35]

The figure on the left side shows the water level is at the 0.5 liter mark, ie half a liter.

1 liter = 1000 mL

0.5*1 liter = 0.5*1000 mL

0.5 liter = 500 mL

If you poured all the water into the jug on the right (without spilling), then the water level should reach the 500 mL mark. This is the small tickmark exactly halfway between the 400 and 600.

5 0
2 years ago
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