The perimeter is 2(length) + 2(width), so 2(x+5) + 2(x+4) = 42 m. In solving for x, you find 6. Plug 6 back into your length and width where x originally was, and you find your length to be 11m, and your width to be 10m. Hope this helps!
f(x)=x3−5
Replace f(x)
with y
.
y=x3−5
Interchange the variables.
x=y3−5
Solve for y
.
Since y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
y3−5=x
Add 5
to both sides of the equation.
y3=5+x
Take the cube root of both sides of the equation to eliminate the exponent on the left side.
y=3√5+x
Solve for y
and replace with f−1(x)
.
Replace the y
with f−1(x)
to show the final answer.
f−1(x)=3√5+x
Set up the composite result function.
f(g(x))
Evaluate f(g(x))
by substituting in the value of g into f
.
(3√5+x)3−5
Simplify each term.
Remove parentheses around 3√5+x
.
f(3√5+x)=3√5+x3−5
Rewrite 3√5+x3
as 5+x
.
f(3√5+x)=5+x−5
Simplify by subtracting numbers.
.
Subtract 5
from 5
.
f(3√5+x)=x+0
Add x
and 0
.
f(3√5+x)=x
Since f(g(x))=x
, f−1(x)=3√5+x is the inverse of f(x)=x3−5
.
f−1(x)=3√5+x
Answer:
2/3
Step-by-step explanation:
To find out what x is in this case, divide 3/4 by 9/8.
3/4 / 9/8
Dividing by a fraction is the same as multiplying it's inverse.
3/4 * 8/9
Cross cancellation (3 & 9 (GCF: 3); 4 & 8 (GCF: 4)
1/1 * 2/3
We can remove the 1/1.
2/3
2/3 is the value of x that will make 3/4 ÷ x = 9/8 true.
Answer:
50 blocks
Step-by-step explanation:
First of all, you need to label you're proportions, which can be mm/blocks.
Then, for 1 block, it is 20 mm because the block is 2 cm, which is equal to 20 mm. So for you're proportion, it is 20 mm/1 block.
Finally, you need to find the total amount of blocks that equals 1000 mm. So you can multiply the 20 mm by 50 to get the 1000 mm. What you do at the top, you do at the bottom, so you also have to do 1 block by 50 to get 50 blocks
So for you're final answer/proportion, it is mm/blocks = 20/1 = 1000/50 and you're final answer is 50 blocks
Hope this helps : )
Answer:C and E
Step-by-step explanation:
