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lana [24]
3 years ago
9

GETS BRAINLIEST AND 11 PTS

Mathematics
2 answers:
TiliK225 [7]3 years ago
6 0
I think the answer to this question is (C) $36.36.
Mazyrski [523]3 years ago
6 0
Hello, 

The surface area of a rectangular prism is:
A=2(xy+xz+yz), where x,y, and z are the dimenisions
We are told that she will spend .09 per in^2, x=11, y=6, and z=8 so we can say cost is:
C=2(9/100)(11*6+11*8+6*8)
C=(18/100)(66+88+48)
C=$36.36


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Write an expression that equals 40.include an exponent
sdas [7]
10'2 X2

20X2




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8 0
3 years ago
Your team wins 18 medals at a competition. The metals are gold, silver, and bronze in a ratio of 2:4:3. How many of each metal d
Anarel [89]

Answer

Find out the how many of each metal did your team win.

To prove

As given

Your team wins 18 medals at a competition.

The metals are gold, silver, and bronze in a ratio of 2:4:3.

Let us assume that x be the scalar multiple of the gold, silver and bronze medal.

Thus

Number of gold medal = 2x

Number of silver medal = 4x

Number of bronze medal = 3x

Than the equation becomes

2x + 4x + 3x = 18

9x = 18

x = \frac{18}{9}

x = 2

Number of gold medal = 2 × 2

                                      = 4

Number of silver medal = 4 × 2

                                       = 8

Number of bronze medal = 3 × 2

                                           = 6

Therefore the number of gold medal are 4, silver medal are 8, bronze medal are 6.

3 0
3 years ago
Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
Please Answer!!!
gavmur [86]
This is the answer, attached below. :)

8 0
3 years ago
A machine fills bags with sweets.
DIA [1.3K]

Answer:

19

Step-by-step explanation:

maximum no. of bag filled by 4275 sweets,is

4275/28 ~=152

therefore , there is 4256 sweets in 152 bags

therefore,4275-4256=19 sweets are left

6 0
3 years ago
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