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GREYUIT [131]
3 years ago
5

Please someone help, I know its kind of a lot, but I need these answers fast pls.

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

Im not sure

Step-by-step explanation:

GOOD LOOK ON YOUR TEST HE DISCONN-ECTED

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CAN SOMEONE PLEASE HELP ME WITH GEOMETRY!! PLEASEEEEE!! I DONT NEED AN ANSWER!! I JUST NEED SOMEONE TO PLEASE EXPLAIN TO ME HOW
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Answer:

I think you have to subtract the to known numbers get the measurements between them.

Step-by-step explanation:

For example, 22 - 11 = 11 so the line segment with the question mark would be 11

I think :)

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Good luck

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Im not sure about this one
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Which number line represents the solution set for the inequality 3x<-9
r-ruslan [8.4K]
The answer would be the 3rd number line or "C"
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3 years ago
Read 2 more answers
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2
\\\\\\\
[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]
\\\\\\
2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)
\\\\\\
\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}
\\\\\\
\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}
\\\\\\
\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}
\\\\\\
\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
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3 years ago
What is 4 ÷ 3/5 ?<br> 6<br> 6 and two-fifths<br> 6 and two thirds<br> 8
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The correct answer is C-6 and two thirds
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3 years ago
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