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2 years ago

5x−4y=34 −x+8y=22 elimination

Mathematics

1 answer:

Brut [27]2 years ago

3 0

Answer:

The solution to the system of equations is:

$x=10,\:y=4$

Step-by-step explanation:

Given the system of equations

$\begin{bmatrix}5x-4y=34\\ -x+8y=22\end{bmatrix}$

Multiply -x+8y=22 by 5: -5x+40y=110

$\begin{bmatrix}5x-4y=34\\ -5x+40y=110\end{bmatrix}$

so adding the equations

$-5x+40y=110$

$+$

$\underline{5x-4y=34}$

$36y=144$

solve 36y = 144 for y:

$36y=144$

divide both sides by 36

$\frac{36y}{36}=\frac{144}{36}$

Simplify

$y=4$

For 5x-4y=34 plug in y=4

$5x-4\cdot \:4=34$

$5x-16=34$

Add 16 to both sides

$5x-16+16=34+16$

Simplify

$5x=50$

Divide both sides by 5

$\frac{5x}{5}=\frac{50}{5}$

Simplify

$x=10$

Therefore, the solution to the system of equations is:

$x=10,\:y=4$

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Please help me answer this I don't understand, I would really appreciate how you solved it as well.

abruzzese [7]

Answer: Parallel

Step-by-step explanation:

Set your -2x+10y=5 equation equal to y

-2x+10y=5

-10y -10y

-2x=5-10y

-5 -5

-2x-5+-10y

-10 -10 -10

-1/5x-1/2=y

Now you can put your equations into your graphing calculator and examine the lines made

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2 years ago

ANSWER !! ILL GIVE 40 POINTS !! DONT SKIP :(( PLUS BRAINLIEST !

stepladder [879]

its X < 1 or x > 3

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2 years ago

Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

The variance = 999,000

The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

= 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean = $\mu = \frac{1}{p}$

= $\mu = \frac{1}{0.001}$

= 1000

Variance = $\sigma ^2=\frac{1-p}{p^2}$

= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

= $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

= $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0

2 years ago

Use the given graph to determine the limit, if it exists. (4 points)

skelet666 [1.2K]

<h3>Answer: 3</h3>

Explanation:

Refer to the graph below. It should be similar to what your teacher gave you, based off the description.

Since we're approaching 3 from the right side, this means we'll be working with the horizontal line portion. We could start at something like x = 3.2 and move closer to 3 by getting to x = 3.1 then x = 3.01 then x = 3.001 and so on. We never actually get to 3 itself.

As x gets closer to 3 from this direction, the y values are approaching 3 since every point on this horizontal line has the same y coordinate. Technically the y value is already at 3, but it's the same idea.

In terms of notation, we can write $\displaystyle \lim_{x\to3^{+}}f(x) = 3$