2 years ago

Find the indicated limit, if it exists.

Mathematics

1 answer:

babymother [125]2 years ago

5 0

Answer: -3

Step-by-step explanation:

-10+7=-3

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Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

rusak2 [61]

Answer:

DNE

Step-by-step explanation:

Given that two particles travel along the space curves

$r_1(t) = (t, t^2, t^3)\\ r_2(t) = (1 + 2t, 1 + 6t, 1 + 14t )$

To find the points of intersection:

At points of intersection both coordinates should be equal.

i.e. r1 =r2

Equate corresponding coordinates

$t=1+2t\\t^2=1+6t\\t^3=1+14t$

I equation gives t =-1

Substitute in II equation to get $t^2 = -5$

i.e. t cannot be real

Hence no point of intersection

DNE

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3 years ago

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Minchanka [31]

Answer:

h(t) = 12-t+6t^2 is a quadratic equation.

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3 years ago

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Write an expression that is equivalent to 6(7 x - x)

Andre45 [30]

Answer:

Step-by-step explanation:

Assuming that you meant 6(7x - x), we get: 6(6x) = 36x

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3 years ago

Thecube of twice a number

lubasha [3.4K]

<h3>Answer:</h3>

The cube of twice a number is $2x^3$ .

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3 years ago

PLEASE PLEASE HELP I will fail if I don't get this in 4 mins

IRISSAK [1]

Answer:

A: input: 10,450; output: 270

B: 10450 - 270x

C: 7750

Step-by-step explanation:

C: 10450 - 270x

10450 - 270(10)

10450 - 2700

7750

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2 years ago