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Eddi Din [679]
3 years ago
15

Solve the division problem. Round answer to the nearest hundredth 9.252.063

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0
My answer is: 9.250.000

I got this answer because the number that is in the hundredths place is the 5. to round, you need to look at the number next to the desired place (the hundredths place), which in this case, is the 2. since the 2 is less than 5, you leave the 5 as it is and your answer will be 9.250.000. :)
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An algebraic expression for ​"59 more than the product of 115 and b​" is <br>____
12345 [234]

Answer:

59 > 115b

Hope this helps

3 0
3 years ago
A farmer has 1,275 seeds. He plants them all in 15 equal rows. A crow comes and eats 5 seeds from each now. How many seeds are l
Eduardwww [97]

Answer:

17 seeds remain

The equation: \frac{1275}{15} / 5

\frac{1275}{15} = 85

85 / 5 = 17

3 0
2 years ago
a line passes through (9, –9) and (10, –5).write an equation for the line in point-slope form. rewrite the equation in standard
Cerrena [4.2K]
The equation of the line in point-slope form is given by:
 y-yo = m (x-xo)&#10;
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 m: slope of the line
 The slope is given by:
 m = \frac{y2-y1}{x2-x1}
 Substituting values:
 m = \frac{-5-(-9)}{10-9}
 Rewriting:
 m = \frac{-5+9}{10-9}
 m = \frac{4}{1}
 m=4
 Now we choose an ordered pair:
 (xo, yo) = (10, -5)&#10;
 Substituting values we have:
 y-(-5)=4(x-10)
 y+5=4(x-10)
 We now rewrite the equation in its standard form:
 y = mx + b&#10;
 Where,
 b: cut with the y axis.
 We have then:
 y = 4x - 40 - 5&#10;&#10;y = 4x - 45
 Answer:
 point-slope form:
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 or
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 standard form
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3 0
3 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0
3 years ago
H=10 cm <br>r= 7cm <br>calculate the volume of the cylinder ​
Stels [109]

Answer:

V = 1538.6 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2h  where r is the radius and h is the height

V = pi (7)^2 10

V = 3.14 (49)10

V = 1538.6 cm^3

7 0
3 years ago
Read 2 more answers
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