Answer: 14/45
Step-by-step explanation:
Assuming that there is no replacements:
The probability of both pens being red will be represented by P(r), and P(b) and P(g) will represents both being blue and green respectively
P(r) = 5/10 x 4/9 = 2/9
P(b) = 3/10 x 2/9 = 1/15
P(g) = 2/10 x 1/9 = 1/45
Now take all 3 probabilities and add them all together to find the probability that any 2 pen will be the same color
P = P(r) + P(b) + P(g)
P = 2/9 + 1/15 + 1/14
P = 14/45
Answer:
1/2
Step-by-step explanation:
both have equal chances
Answer:
5
Step-by-step explanation:
Given :
Y α 1/x
Y = k/x
Where, k = constant of proportionality ;
y = 3 ; x = 10
3 = k / 10
k = 10 * 3
k = 30
Equation becomes :
Y = 30/x
Y =? ; when x = 6
Y = 30 / 6
Y = 5
Answer:
- a° = 70°
- b° = 78°
- c° = 139°
- d° = 17°
- e° = 123°
- f° = 69.5°
Step-by-step explanation:
You need to take advantage of what you have learned about inscribed angles. Each inscribe angle is half the measure of the arc it intercepts. Of course, the sum of all arcs around a circle is 360°.
Putting these facts together, you can quickly conclude that opposite angles of an inscribed quadrilateral are supplementary:
a = 180 -110 = 70
b = 180 -102 = 78
The arc (c+81) is opposite the inscribed angle marked 110, so we have ...
c + 81 = 2(110)
c = 220 -81 = 139
The arc (c+d) is intercepted by the angle marked b, so we have ...
139 +d = 2(78)
d = 156 -139 = 17
The arc (e+81) is intercepted by the inscribed angle marked 102, so ...
e +81 = 2(102)
e = 204 -81 = 123
The inscribed angle f intercepts arc c, so is half its measure.
f = 139/2 = 69.5
Answer:
![j \: < \: 48](https://tex.z-dn.net/?f=j%20%20%5C%3A%20%20%3C%20%20%5C%3A%2048)
Step-by-step explanation:
We want to solve the inequality
![\frac{1}{4}j - 8 \: < \: 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7Dj%20-%208%20%20%5C%3A%20%3C%20%20%5C%3A%204)
We add 8 to both sides to get:
![\frac{1}{4}j \: < \: 4 + 8](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7Dj%20%5C%3A%20%20%3C%20%20%5C%3A%204%20%2B%208)
![\frac{1}{4} j \: < \: 12](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20j%20%5C%3A%20%20%3C%20%20%5C%3A%2012)
Multiply both sides by 4 to get:
![j \: < \: 12 \times 4](https://tex.z-dn.net/?f=j%20%20%5C%3A%20%20%3C%20%20%5C%3A%2012%20%5Ctimes%204)
![j \: < \: 48](https://tex.z-dn.net/?f=j%20%20%5C%3A%20%20%3C%20%20%5C%3A%2048)