Answer:
For tingle #1
We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.



We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.
For triangle #2
In this one, we can find everything and there is one one value for each.
- We can find side c
Since we have a right triangle, we can find side c using the Pythagorean theorem






- We can find angle C using the cosine trig identity




- Now we can find angle A using the triangle sum theorem



For triangle #3
Again, we can find everything and there is one one value for each.
- We can find angle A using the triangle sum theorem



- We can find side a using the tangent trig identity




- Now we can find side b using the Pythagorean theorem




I believe the answer is (z - 1)(z - 12).
Hope this helps!
130 percent
Of means multiply
P * 800 = 1040
Divide by 800
P * 800/800 = 1040/800
P = 1.3
Multiply by 100 to get percent
130 percent
Answer:
Correct option is (C).
The possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
Step-by-step explanation:
The <em>p</em>-value is the probability of acquiring a result as extreme as the observed result, assuming the null hypothesis statement is true.
The <em>p</em> value of a test is:
Left-tailed test:
Right-tailed test:
.
Here,
TS = Test statistic
ts = computed value of the test statistic.
The two-tailed <em>p</em>-value is:
or
.
The <em>p</em>-value of the two tailed test is, 0.44.
Compute the <em>p</em>-value for one-tailed test a follows:


Thus, the possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
The correct option is (C).
6t-10is the awsner. If s is the number of nautical miles separating the ships, express s in terms of t(the number of hours after 12 noon). I formed the equation s squared to the second power equals (12t) squard to the second power + (10 - 16) squared to the second power