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2 years ago

Look at the question below.

Mathematics

2 answers:

andriy [413]2 years ago

7 0

Choice c !!!! Hope it helps

sweet-ann [11.9K]2 years ago

6 0

Answer: bottom left

4x+2y+15

Step-by-step explanation:

3x + x=4x

5 + 10= 15

2y=2y

4x+2y+15

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Logic You find that the product of 93 and 6 is 558. He can you use addition to check your answer ? How can you use division yo c

frozen [14]

Addition: 93 can be added six times to determine the total

and division can be used to check your answer since it's the inverse operation of multiplication...take your solution of 558 and divide it by 6 (or 93) to see if 93 times six equals 558

3 0

3 years ago

Does someone know how to do this?

amid [387]

3√x+2 = √x+4

divide both sides by 3

√x+2 = √x+4 / 3

remove radical by squaring both sides

x+2 = x+4/9

x+2 = x/9 + 4/9 =

8x/9 = -14/9

8x*9 = -14*9=

72x = -126

x = -7/4

8 0

3 years ago

Read 2 more answers

Is the product of two rational numbers always rational or always irrational or neither

Bad White [126]

Answer:

$Always$ $rational$

Step-by-step explanation:

The product of two rational numbers is always rational.

3 0

3 years ago

A straight line is to a ruler as an angle is to:

r-ruslan [8.4K]

Answer:

a protractor

Step-by-step explanation:

You measure a straight line with a ruler

You measure an angle with a protractor

4 0

2 years ago

Read 2 more answers

A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his pro

Anestetic [448]

Answer:

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

Step-by-step explanation:

Given that, a homeowner plans to enclose a 200 square foot rectangle playground.

Let the width of the playground be y and the length of the playground be x which is the side along the boundary.

The perimeter of the playground is = 2(length +width)

=2(x+y) foot

The material costs $1 per foot.

Therefore total cost to give boundary of the play ground

=$[ 2(x+y)×1]

=$[2(x+y)]

But the neighbor will play one third of the side x foot.

So the neighbor will play $=\$(\frac13x)$

Now homeowner's total cost for the material is

$=\$[ 2(x+y)-\frac13x]$

$=\$[2x+2y-\frac13x]$

$=\$[2y+x+x-\frac13x]$

$=\$[2y+x+\frac{3x-x}{3}]$

$=\$[2y+x+\frac{2}{3}x]$

$=\$[2y+\frac53x]$

$\therefore C(x)=2y+\frac53x$

where C(x) is total cost of material in $.

Given that the area of the playground is 200.

We know that,

The area of a rectangle is =length×width

=xy square foot

∴xy=200

$\Rightarrow y=\frac{200}{x}$

Putting the value of y in C(x)

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

The domain of C is $(0,\infty )$ .

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

Differentiating with respect to x

$C'(x)= - \frac{400}{x^2}+\frac53$

Again differentiating with respect to x

$C''(x) = \frac{800}{x^3}$

To find the critical point set C'(x)=0

$\therefore 0= - \frac{400}{x^2}+\frac53$

$\Rightarrow \frac{400}{x^2}=\frac{5}{3}$

$\Rightarrow x^2 =\frac{400\times 3}{5}$

$\Rightarrow x=\sqrt{240}$

$\Rightarrow x=15.49 \approx15.5$

Therefore

$\left C''(x) \right|_{x=15.5}=\frac{800}{15.5^3}>0$

Therefore at x= 15.5 , C(x) is minimum.

Putting the value of x in $y=\frac{200}{x}$ we get

$\therefore y=\frac{200}{15.5}$

=12.9

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

6 0

3 years ago