Question

Evaluate limB3%7D%20%2B%202x%20%2B%206%20%7D%20" id="TexFormula1" title=" \frac{3 {x}^{2} + 5x - 1 }{4 {x}^{3} + 2x + 6 } " alt=" \frac{3 {x}^{2} + 5x - 1 }{4 {x}^{3} + 2x + 6 } " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$\lim_{x \to 0} =-\frac{1}{6}$

Step-by-step explanation:

The first step in evaluating a limit should be to plug in the number to see if you get a result

When you plug in 0 to all of the x's in the expression, you are left with the constants -1 on the top and 6 on the bottom of the fraction.

So there's no need to go any further, the limit as x approaches 0 is $-\frac{1}{6}$

Answer 2

Answer:

-1/6

Step-by-step explanation:

To find the limit as x approaches 0 we can just plug in 0

for the numerator: 3*0+5*0-1 = -1

For the denominator: 4*0+2*0+6= 6

answer is just -1/6 or -.16666666666666666666667