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lana66690 [7]
3 years ago
12

!ugshjdjhsdh sjdgjhds jsdghjhsbjhsgfhdhfgff..

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

nehsnebekdbeibewokdjedjebejehwkdhwnejeu

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The last one I think
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A door of a lecture hall is in a parabolic shape. The door is 56 inches across at the bottom of the door and parallel to the flo
Arada [10]

Answer:

The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. (See attachment included below). Head must 15.652 inches away from the edge of the door.

Step-by-step explanation:

A parabola is represented by the following mathematical expression:

y - k = C \cdot (x-h)^{2}

Where:

h - Horizontal component of the vertix, measured in inches.

k - Vertical component of the vertix, measured in inches.

C - Parabola constant, dimensionless. (Where vertix is an absolute maximum when C < 0 or an absolute minimum when C > 0)

For the design of the door, the parabola must have an absolute maximum and x-intercepts must exist. The following information is required after considering symmetry:

V (x,y) = (0, 32) (Vertix)

A (x, y) = (-28, 0) (x-Intercept)

B (x,y) = (28. 0) (x-Intercept)

The following equation are constructed from the definition of a parabola:

0-32 = C \cdot (28 - 0)^{2}

-32 = 784\cdot C

C = -\frac{2}{49}

The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. Now, the representation of the equation is included below as attachment.

At x = 0 inches and y = 22 inches, the distance from the edge of the door that head must observed to avoid being hit is:

y -32 = -\frac{2}{49} \cdot x^{2}

x^{2} = -\frac{49}{2}\cdot (y-32)

x = \sqrt{-\frac{49}{2}\cdot (y-32) }

If y = 22 inches, then x is:

x = \sqrt{-\frac{49}{2}\cdot (22-32)}

x = \pm 7\sqrt{5}\,in

x \approx \pm 15.652\,in

Head must 15.652 inches away from the edge of the door.

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14b=a|\div14\\&#10;b=\dfrac{a}{14}
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The area of a circle (A) is given by the formula A=r^2 where r is the circle's radius. The formula to find r is______ . If (A)=5
9966 [12]

Answer: (A)   and   (A)

<u>Step-by-step explanation:</u>

A=\pi \cdot r^2\\\\\dfrac{A}{\pi}=r^2\\\\\sqrt{\dfrac{A}{\pi}}=r\ \rightarrow \ \bigg(\dfrac{A}{\pi}\bigg)^{\dfrac{1}{2}}\\\\\\\\r=\sqrt{\dfrac{A}{\pi}}\\\\.\ =\sqrt{\dfrac{54\cdot 7}{22}}\\\\.\ =\sqrt{\dfrac{27\cdot 7}{11}}\\\\.\ =\sqrt{\dfrac{189}{11}}\\\\.\ =\sqrt{17.1818}\\\\.\ =4.15

8 0
3 years ago
What is the distance between the points (−7, 1) and (−7, −5) on the coordinate plane?
4vir4ik [10]

Answer:

\displaystyle d = 6

General Formulas and Concepts:
<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Coordinate Planes

  • Coordinates (x, y)

<u>Algebra II</u>

Distance Formula: \displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

Point (-7, 1)

Point (-7, -5)

<u>Step 2: Find distance </u><u><em>d</em></u>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>.

  1. Substitute in points [Distance Formula]:                                                     \displaystyle d = \sqrt{(-7 - -7)^2 + (-5 - 1)^2}
  2. [Order of Operations] Evaluate:                                                                  \displaystyle d = 6
6 0
3 years ago
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