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lana66690 [7]
3 years ago
12

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Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

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The length of a rectangle is 5 more inches more than the width. The perimeter is 46 inches. Find the length and the width.
natta225 [31]

Answer: w = 9 inches

              w + 5 = 14 inches

Step-by-step explanation:

5 0
3 years ago
If someone could explain this to me that be really great :p
BigorU [14]
"x" always goes on the left side and "y" always goes on the right side of the parentheses. If you only have an "x" then you will just put a zero in for "y" and vice versa. I hope this helps.
4 0
3 years ago
The length of a rectangle is 5 times larger than x. The width is 4 cm less than the length. The perimeter is at least 96 cm. Wha
Ede4ka [16]

We know that the perimeter of a rectangle = 2(l + w)

l = length

w = width

In our problem,

l = 5x

w = 5x - 4

Let's create an inequality to help us solve this problem.

2(5x + (5x - 4)) ≥ 96

Let's start off by simplifying the terms inside the parentheses.

2(10x - 4) ≥ 96

Distribute the 2

20x - 8 ≥ 96

Add 8 to both sides.

20x ≥ 104

Divide both sides by 20

x ≥ 5.2

Let's plug 5.2 into x for our length and width.

Length = 5x = 5(5.2) = 26 cm

Width = 5x - 4 = 5(5.2) - 4 = 26 - 4 = 22 cm

The smallest possible dimensions for the rectangle are, length = 26 cm and width = 22 cm  

6 0
3 years ago
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postnew [5]
4 over 3.2 and 6 over 4.8
8 0
3 years ago
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Solve this proportion: 1/c+5=2/3
Fittoniya [83]
\frac{1}{c} +5=\frac{2}{3}\ \|\ subtract\ 5\ to\ both\ sides  \\\\\frac{1}{c} =\frac{2}{3}-5\\\\\frac{1}{c} =\frac{2}{3}-\frac{15}{3}\\\\\frac{1}{c} = \frac{-13}{3}\\\\-13c=3\ \ | \ divide \ both \ sides\  by\ (-13)\\\\c=-\frac{3}{13}



\frac{1}{c+5} = \frac{2}{3} \\\\2(c+5) =3\\\\2c+10=3\ \ |\ subtract\ 10\ to\ both\ sides  \\\\ 2c=3-10 \\\\2c=-7 \ \ | \ divide \ both \ sides\  by\  2 \\\\c=-\frac{7}{2}\\\\c=-3.5
6 0
3 years ago
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