Let x and y be width and length of the plot to be fenced. Therefore,
Area (A) = xy m^2
If the side bordering the river is x, then
Circumference (C) = 8500 = x+2y => x = 8500-2y
Substituting for w in the equation for A;
A = (8500-2y)y = 8500y -2y^2
For maximum area, derivative of A with respect to y is 0. That is;
dA/dy = 0 = 8500 -4y => 4y = 8500 => y = 8500/4 = 2125 m
And, x = 8500-2y = 8500 -2*2125 = 4250 m
Therefore,
One side = 4,250 m and second side = 2,125 m.
Largest area, A = 4250*2125 = 9,031,250 m^2
Answer: (BRAINLIEST PLEASE)
120 g.
Step-by-step explanation:
Answer: I don't get the question, can you clarify?
Step-by-step explanation:
The reduced fee is $3. If 6 rounds is $32 and the first round is $17, subtract 17 from 32 and you get 15. Divide that by 5 because there are five rounds left, you get $3
Answer:
Step-by-step explanation:
<u>Step 1: Make an equation</u>
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<u>Step 2: Cross multiply</u>
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<u>Step 3: Divide both sides by 32</u>
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Answer:
