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alexira [117]
3 years ago
14

E is between D and F. Solve for each segmant length

Mathematics
2 answers:
Julli [10]3 years ago
6 0

Answer:

DE = 32

EF = 34

Step-by-step explanation:

3x + 5 + 4x - 2 = 66

7x + 3 = 66

7x = 63

x = 9

DE = 3(9)+5 = 32

EF = 4(9)-2 = 34

check:  32 + 34 = 66

Gala2k [10]3 years ago
6 0

Answer:

DE = 32

EF = 34

DF = 66

Step-by-step explanation:

DE + EF = DF from the segment addition postulate

3x+5  + 4x-2 = 66

Combine like terms

7x+3 = 66

Subtract 3 from each side

7x+3-3 = 66-3

7x = 63

Divide each side by 7

7x/7 = 63/7

x = 9

DE = 3x+5 = 3(9)+5 = 27+5 = 32

EF = 4x-2 = 4(9) -2 = 36-2 = 34

DF = 66

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