All categories

2 years ago

Find the equation of the line that passes through (5, -1) and (-10, -10)

Mathematics

1 answer:

SashulF [63]2 years ago

3 0

Answer:

y = 0.6x – 4

y = 3/5x -4

Step-by-step explanation:

You might be interested in

Work out<br> (9×10²)+(7×10³)<br> State your answer in standard form

Sunny_sXe [5.5K]

Answer:

(9×10×10)+(7×10×10)

900+700

1600

1.6×10^3

4 0

2 years ago

Question

Serhud [2]

Answer:

The value of k is 11.

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

2=(k-3)/(5-1)

2=(k-3)/4

2*4=k-3

8=k-3

k=8+3

k=11

6 0

2 years ago

The lengths of the bases of a trapezoid are 17 inches and 10 inches. The trapezoid has an area of 189 square inches.

Mamont248 [21]

Answer:

height of this trapezoid is 14 inches.

Step-by-step explanation:

$\boxed{Area -of -trapezoid=\frac{a+b}{2} h}$

[ Here lengths, a = 17 and b = 10 and area of trapezium given 189 ]

using the formula:

$\frac{17+10}{2} *h = 189$

$\frac{27}{2} h = 189$

$h = \frac{189*2}{27}$

$h =14$

For more trapezoid related questions: https://brainly.in/question/35963763

6 0

2 years ago

Read 2 more answers

Which expression is equivalent to ? Assume.

nikdorinn [45]

Answer:

2. $-2x^{8}y^{18}$

Step-by-step explanation:

We have been given an expression $\frac{10x^{6}y^{12}}{-5x^{-2}y^{-6}}$ and we are asked to find equivalent expression to our given expression.

Using fraction rule $\frac{a}{-b} =-\frac{a}{b}$ we can write our expression as: $-\frac{10x^{6}y^{12}}{5x^{-2}y^{-6}}$ .

Upon dividing 10 by 5 we will get,

$-\frac{2x^{6}y^{12}}{x^{-2}y^{-6}}$

Upon using exponent property for quotient $(\frac{a^{m}}{a^{n}} =a^{(m-n)})$ we will get,

$-\frac{2x^{6}y^{12}}{x^{-2}y^{-6}}=-2x^{(6--2)}y^{(12--6)}$

$-2x^{(6+2)}y^{(12+6)}$

$-2x^{8}y^{18}$

Therefore, our expression simplifies as $-2x^{8}y^{18}$ and 2nd option is the correct choice.

6 0

3 years ago

Read 2 more answers

dybincka [34]

Answer:

$57.2\ ft$

Step-by-step explanation:

we know that

The formula of slope is "rise over run", where the "rise" (means change in y, up or down) and the "run" (means change in x, left or right)

In this problem

The tangent of angle of 5 degrees is equal to the quotient of "rise over run"

Let

y ----> the rise of the ramp

x ----> the run of the ramp

$tan(5^o)=\frac{y}{x}$

we have

$y=5\ ft$

substitute and solve for x

$tan(5^o)=\frac{5}{x}$

$x=\frac{5}{tan(5^o)}$

$x=57.2\ ft$

5 0

3 years ago