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AleksandrR [38]
3 years ago
15

Given f(x) = 3x- 1 and g(x) = 2x-3, for which value of x does g(x) = f(2)?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer: x = 4

Step-by-step explanation: f(2) = 3(2)-1 = 5. Meaning x needs to be a value that makes g(x) = 5. You can set them up equal to each other 5 = 2x-3 and solve. You end up getting x = 4.

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Describe how to compare the two ratios 5:8 to 7:9. Tell each step to set up the ratios, then explain what to do to be able to co
lutik1710 [3]

Answer:

5/8 is smaller.

Step-by-step explanation:

A ratio is just a different type of fraction, a 5:8 ratio means 5/8 which is 0.625. A 7:9 ratio equals 7/9 which is 0.777777

Then to compare them you see which is smaller or bigger.

0.77777  is bigger than 0.625 so we know that 0.77777777 which was the 7:9 ratio is the bigger one.

3 0
1 year ago
Read 2 more answers
Need help with this problem explain pls
Usimov [2.4K]
All sides of an equilateral triangle are equal, so all three sides are 9 cm.
To find h, use the pythagorean theorem. This requires use of only one right triangle, where we use b as our h.

a^2+b^2=c^2
(4.5)^2+b^2=(9)^2
(20.25)+b^2=(81)
b^2=(81/20.25) or 4
square root both sides
b=2
6 0
3 years ago
This is inequality and solution. plz help. im stuck. THIS IS URGENT
olya-2409 [2.1K]
I hope this helps you



x>4


x>-4


x>4
6 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
State the property.<br>4(2+3)=(2+3)4​
Komok [63]

Hmm, it looks like it could be commutative property of multiplication.

The order of the expression is different.

4(2+3)=

4(5)=20

(2+3)4=

(5)4= 20

8 0
3 years ago
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