All categories

3 years ago

Given f(x) = 3x- 1 and g(x) = 2x-3, for which value of x does g(x) = f(2)?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

6 0

Answer: x = 4

Step-by-step explanation: f(2) = 3(2)-1 = 5. Meaning x needs to be a value that makes g(x) = 5. You can set them up equal to each other 5 = 2x-3 and solve. You end up getting x = 4.

You might be interested in

Sally eats lunch at a restaurant and her bill is $12. She would like to leave a 15% tip for the waiter.

Andreas93 [3]

Answer:

$ 13.80

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A building with a height of 14 m casts a shadow that is 16 m long while a taller building casts a 24 m long shadow. What is the

uranmaximum [27]

26 i am not really sure cuz what i did was 16-14= 2
2+24= 26

5 0

3 years ago

Read 2 more answers

~please help, thank you~

solong [7]

The volume of a pyramid with hight and base is 1/3 the volume of a rectangleular prisim with the same height and base

also the volume of a cone is 1/3 the volume of a cylinder with same height and base so
just fun facts to know (helpful)

so volume of cylinder=1/3 times height tiimes pi times radius^2
subsitute
use pi=3.14
height=12
radius=6
volume=1/3 times 12 times 3.14 times 6^2
volume=4 times 3.14 times 36
volume=452.16 cubic meters
the naswer is the top left choice

6 0

4 years ago

Read 2 more answers

A fisherman sold some big fish at $4 each and twice as many small fish at

harina [27]

Answer:

The answer is 12 big fish.

5 0

3 years ago

At the center of espionage in Kznatropsk one is thinking of a new method for sending Morse telegrams. Instead of using the tradi

alexgriva [62]

Answer:

It takes less time sending 5 letters the traditional way with a probability of 36.7%.

Step-by-step explanation:

First we must take into account that:

- The traditional method is distributed X ~ Poisson(L = 1)

- The new method is distributed X ~ Poisson(L = 5)

$P(X=x)=\frac{L^{x}e^{-L}}{x!}$

Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events (to send 5 letters) in a unit of time for both methods, so:

- For the traditional method:

$P(X=5)=\frac{1^{5}e^{-1}}{1!}\\\\P(X=5) = 0.367$

- For the new method:

$P(X=5)=\frac{5^{5}e^{-5}}{5!}\\\\P(X=5) = 0.175$

According to this calculations we have a higher probability of sending 5 letters with the traditional method in a unit of time, that is 36.7%. Whereas sending 5 letters with the new method is less probable in a unit of time. In other words, we have more events per unit of time with the traditional method.

7 0

3 years ago