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Nana76 [90]
3 years ago
9

Helllllllp please ASAP​

Mathematics
2 answers:
fgiga [73]3 years ago
6 0

Answer:

The second one

Step-by-step explanation:

igor_vitrenko [27]3 years ago
4 0

Answer: B

Step-by-step explanation:

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4) This results when you flip the numerator and denominator of a fraction.
Semenov [28]

Answer:

To divide one fraction by another one, flip numerator and denominator of the second one, and then multiply the two fractions. The flipped-over fraction is called the multiplicative inverse or reciprocal.

Step-by-step explanation:

I got this from google.

3 0
3 years ago
How to find slope y=3x+5
klemol [59]

This equation is in slope-intercept form; y = mx+b.

m is the slope and b is the y-intercept, so to find the slope you'd look at the coefficient of x.

In this equation, y = 3x+5, the coefficient of x is 3, so that means that the slope of this equation is 3.

Answer is:

3 is the slope

3 0
3 years ago
If f(x) = 5x − 1 and g(x) = 2x2 + 1, what is the value of (f × g)(-3)?
Softa [21]

f(x) = 5x − 1 and g(x) = 2x^2 + 1

(f × g)(x) =  (5x − 1)(2x^2 + 1)

(f × g)(x) = 10x^3 - 2x^2 + 5x - 1

Substitute x = - 3

(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1

(f × g)(-3) = 10(-27) - 2(9) -15 - 1

(f × g)(-3) =-270 - 18 - 16

(f × g)(-3) = -236

Answer

- 236

6 0
3 years ago
When modeling hourly pay, which part of the equation is used to represent the<br> hourly rate?
lesantik [10]

Answer:

y = mx + b

Step-by-step explanation:

The reason is,  x is always the hour, and m is the amount of money you earn in the hours.

3 0
3 years ago
Find cscθ.<br><br>pls answer
ExtremeBDS [4]

Answer:

The answer to your question is csc Ф = \frac{-5}{4}

Step-by-step explanation:

Process

1.- Determine the sign

We must determine csc Ф in the forth quadrangle, here csc is negative.

2.- Determine the hypotenuse

     c² = a² + b²

     c² = 3² + (-4)²

     c² = 9 + 16

     c² = 25

     c = 5

3.- Determine csc Ф

    csc Ф = \frac{hypotenuse}{opposite side}

    csc Ф = \frac{5}{-4}  = \frac{-5}{4}

7 0
2 years ago
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