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Fantom [35]
3 years ago
11

1. Which situation could the equation – 5 x 10 = -50 or 5x(- 10) = – 50 represent.

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

both of them are correct

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A point is randomly chosen on a map of North America. Describe the probability of the point being in each location: North Americ
Aleks04 [339]

Answer:

We know that the map is of North America:

The probabilities are:

1) North America:

As the map is a map of North America, you can point at any part of the map and you will be pointing at North America, so the probability is p = 1

or 100% in percentage form.

2) New York City.

Here we can think this as:

The map of North America is an extension of area, and New Yorck City has a given area.

As larger is the area of the city, more probable to being randomly choosen, so to find the exact probability we need to find the quotient between the area of New York City and the total area of North America:

New York City = 730km^2

North America = 24,709,000 km^2

So the probability of randomly pointing at New York City is:

P = ( 730km^2)/(24,709,000 km^2) = 3x10^-5 or 0.003%

3) Europe:

As this is a map of Noth America, you can not randomly point at Europe in it (Europe is other continent).

So the probaility is 0 or 0%.

5 0
3 years ago
What is the value of x?
blsea [12.9K]
Since these are supplementary angles  (two angles which sum to 180°) we can say:

4x+x=180  combine like terms on left side

5x=180  divide both sides by 5

x=36°
3 0
3 years ago
Make x the subject of the formula a − bx = c​
Eddi Din [679]

Answer:

x = c - a / -b

Step-by-step explanation:

a - bx = c

-a               -a

-bx = c - a

divide -b    

x = c - a / -b

3 0
2 years ago
Read 2 more answers
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
P= $790, t= 3, r=4% compounded continuously : Find A
Savatey [412]
\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$790\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &3
\end{cases}
\\\\\\
A=790e^{0.04\cdot 3}\implies A=790e^{0.12}
8 0
3 years ago
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