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klasskru [66]
3 years ago
9

Question leads a person to aParticular awnser

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0
What are we supposed answer towards this question?
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Find a unit vector that is orthogonal to both i + j and i + k.
kenny6666 [7]

Answer: i - j - k

Step-by-step explanation:

Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.

<1,1,0> x <1,0,1>

det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )

the determinate of the matrix: <1,-(1),-1>

or: i - j - k

3 0
3 years ago
F(x)= 2x^2 + k/x point of inflection at x=-1 then value of k is
Nady [450]
I think it isss 2 :)))
4 0
4 years ago
Julissa gave out an equal number of oranges to each of the 6 apartments on her floor. If she gave each apartment 5 oranges, how
dybincka [34]

Answer:

30 oranges

Step-by-step explanation:

Total number of apartment in julissa floor = 6

Number of oranges given to each apartment = 5

how many oranges did Julissa give out in all?

Total number of oranges julissa's gave out = Total number of apartment in julissa floor × Number of oranges given to each apartment

= 6 × 5

= 30 oranges

Therefore, total number of oranges julissa gave out = 30

4 0
3 years ago
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PLS HELP I'LL GIVE THE BRAINLEST
Alecsey [184]

Answer: The graph on bottom right

Step-by-step explanation:

It’s the only one that correctly depicts the time (6 hours) and distance (300 miles) traveled. Starting at zero miles and zero drive time, it’s the only one that goes through 300 miles over a period of 6 hours.

4 0
3 years ago
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Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?
Alja [10]

Answer:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: (a +b)^n, n > 0

Now, the BINOMIAL EXPANSION is the expansion which  describes the algebraic expansion of powers of a binomial.

Here, (a+b)^n  = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}

or, on simplification, the terms of the expansion are:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

The above statement holds for each  n > 0

Hence, the complete expansion for the given expression is given as above.

4 0
3 years ago
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