Answer:
2.4
Step-by-step explanation:
12/5=2.4
The cooper's weight as an adult dog will be 90 pounds.
<h3>
What is percentage?</h3>
Percentage, which is a relative figure used to denote hundredths of any quantity. One percent (symbolized as 1%) is equal to 100 parts; hence, 100 percent denotes the complete amount, and 200 percent designates double the amount specified.
A typical method for calculating a percentage is the formula shown below:
- Determine the total amount of what you want to find a percentage.
- Divide the number to determine the percentage.
- Multiply the value by 100.
Calculation for the weight of Cooper as an adult;
Cooper's present weight is 20 pounds.
He will weigh about 350% as much as his current weight.
Calculate 350% of 20 pounds.
= (350×20)/100
= 70
The increment of the weight of Cooper will be 70 pounds.
Thus, the total weight is 20 + 70 = 90.
Therefore, the weight of Cooper after 350% as an adult would be 90 pounds.
To know more about the percent change, here
brainly.com/question/809966
#SPJ4
3 projects.
12/4=3. Please mark me brainliest rly wanna mark up!
Answer:
Pretty sure its 40
Step-by-step explanation:
There is only 3 odd numbers on a 6 sided dice (1, 3, 5) and you would just divide 120 and 3
<span>Equation at the end of step 1 :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0
</span><span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> -3x3y7 + x3y - 6y</span> = <span> -y • (3x3y6 - x3 + 6)</span>
Trying to factor a multi variable polynomial :
<span> 3.2 </span> Factoring <span> 3x3y6 - x3 + 6</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
<span>Equation at the end of step 3 :</span><span> -y • (3x3y6 - x3 + 6) = 0
</span><span>Step 4 :</span>Theory - Roots of a product :
<span> 4.1 </span> A product of several terms equals zero.<span>
</span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span>
</span>We shall now solve each term = 0 separately<span>
</span>In other words, we are going to solve as many equations as there are terms in the product<span>
</span>Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : -y = 0<span>
</span>Multiply both sides of the equation by (-1) : y = 0