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ankoles [38]
2 years ago
7

I need some help on these. this is due tomorrow and my teacher showed me how to do them but i still didn't understand how to do

them. please help me

Mathematics
1 answer:
arsen [322]2 years ago
3 0
All triangles have angles that add up to 180 so the first one add 76 and 59 and subtract that from 180 to get the missing angle remember EACH triangle is 180 degrees when ALL the angles are added together on the ones with x solve for x then figure out the answer from there hope this helps
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Evaluate the function
Sedaia [141]

f(0) =  {4}^{3 \times 0  + 3}  =  {4}^{0 + 3}  =  {4}^{3}  = 64
The answer is above.
Additional note 1:
{4}^{3}  = 4 \times 4 \times 4 = 16 \times 4 = 64
Additional note 2:
In the answer I filled in "0" at the place where "n" was. This is because the question tells us n=0
4 0
3 years ago
Three ways to write 3 to the 5th power
cestrela7 [59]

First expression

=>  3 x  3 x  3 x 3 x 3 – In this expression, we multiplied 3 5 times and the product is 243

Second expression

=> 3 ^ 5 , in where ^ read as raised to the power. , the product is also 243

Third expression

=> 3^2 x 3 ^3

=> (3 x 3) x (3 x 3 x 3)

=> 9 x 27, the product is also equals to 243.

7 0
2 years ago
Read 2 more answers
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Marisol has 486 square inches of wrapping paper
AfilCa [17]

Answer:

9 inches

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
On Monday, Kym spent 15 minutes folding the clothes. She took a bath for 25 minutes and then took 10 minutes to make her bed. Ky
Brut [27]
Ok. First, Kym went to bed at 8:30. There are only 60 minutes in an hour. 10 minutes to make her bed. 8:30 - 10 = 8:20. She had a 25 minute bath "jeez that's long" 8:20 - 25 = 7:55. Kym spent 15 minutes folding clothes: 7:55 - 15 = 7:40. She began to start folding clothes at 7:40.

Answer:<span> B. 7:40 p.m.
Or you could do it the easy way.
15 + 25 + 10 = 50

50 - 8:30 = 7:40
</span>

7 0
3 years ago
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