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kipiarov [429]
3 years ago
5

A triangle has angle measurements of 59°, 52°, and 69°. What kind of triangle is it?

Mathematics
2 answers:
Tema [17]3 years ago
5 0

Answer:

Acute Triangle

Step-by-step explanation:

since all of the angles are below 90° the triangle is acute

Volgvan3 years ago
4 0

Answer:

\huge\boxed{\sf Scalene \ Triangle}

Step-by-step explanation:

The angles measurements are 59°, 52° and 69°. The triangle which have all of its angles and sides unequal is called a scalene triangle.

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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Giveing 15 points.Use the rectangle to find the measure of the following angles measure ane BAC=25
Vinil7 [7]

1) All angles of a rectangle are right angles, so the measure of angle CBA is 90 degrees.

2) Since all angles of a rectangle are right angles, angle BAD measures 90 degrees. Subtracting the 25 degrees of angle BAW from this, we get that angle CAD has a measure of 65 degrees.

3) Opposite sides of a rectangle are parallel, so by the alternate interior angles theorem, the measure of angle ACD is 25 degrees.

4) Because diagonals of a rectangle are congruent and bisect each other, this means BW=WA. So, since angles opposite equal sides in a triangle (in this case triangle ABW) are equal, the measure of angle ABW is 25 degrees. This means that the measure of angle CBD is 90-25=65 degrees.

5) In triangle AWB, since angles in a triangle add to 180 degrees, angle BWA measures 130 degrees.

6) Once again, since diagonals of a rectangle are congruent and bisect each other, AW=WD. So, the measures of angles WAD and ADW are each 65 degrees. Thus, because angles in a triangle (in this case triangle AWD) add to 180 degrees, the measure of angle AWD is 50 degrees.

4 0
2 years ago
Could use some help!
Natasha_Volkova [10]


[6, ∞) , x >= 6 so

answer is D. last one

6<= x < ∞
6 0
3 years ago
This is the other question!
joja [24]
I’m not 100% true but i think it’s false, true, true :)
6 0
2 years ago
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You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
Which number line correctly graphs the numbers in the list?​
Oksana_A [137]

Answer:

the first option

Step-by-step explanation:

8 0
2 years ago
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