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Anna11 [10]
3 years ago
12

1.) What is the relationship between sine & cosine?

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0
It's A ...cos (90- theta) = sin theta

so A
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X -4 ifx&gt;4<br> |<br> Rsm question
Sav [38]

Answer:

x>4

d'ou: x-4>4-4

x-4>0 voilà bonnne journée

Step-by-step explanation:

3 0
2 years ago
What day and time will it be 85 hr 33 min after Friday 12:11 am?
marishachu [46]

Answer:

Enter date and time information at "From:"

Select a month and a day. Enter a year.

The year entered must be a positive number. Not zero (0).

Enter hours and minutes. Select am or pm.

The hours entered must be a positive number between 1 and 12 or zero (0).

The minutes entered must be a positive number between 1 and 59 or zero (0).

Add or Subtract Line

Enter number of days, hours and minutes

Select "add" or "subtract"

If you type "ghblxz", in the year box the computer will print "0"

If you type "1.9e2", the computer will use "190" to calculate the answer.

If you select "February 31", the computer will print "Not a Day"

Click "Click to Calculate" button. The calculated date and time will appear.

NaN = not a number

To clear the entry boxes click "Reset

5 0
2 years ago
Amanda bought 2 CDs that were each the same price. Including sales tax, she paid a total of $29.80. Each CD had a tax of $1.10 .
Len [333]

Answer:

13.80 there you go buddy

6 0
3 years ago
A newspaper is launching a new advertising campaign in order to increase the number of daily subscribers. The newspaper currentl
BARSIC [14]

Answer:

57 days

Step-by-step explanation:

Given that:

t(0) = 26000

Growth rate (S'(t)) = 80t^1/2

Targeted number of subscribers = 49000

Take the integral of the growth rate :

∫80t^1/2dt = [(80t^(1/2 + 1)) / 1/2 + 1] + C

[(80t^(1/2 + 1)) / 1/2 + 1] + C = (80t^3/2) / 3/2 + C

(80t^3/2) * 3/2 + C = (160/3)t^3/2 + C

(160/3)t^3/2 + C

Let C = t(0)

(160/3)t^3/2 + 26000 = 49000

(160/3)t^3/2 = 49000 - 26000

(160/3)t^3/2 = 23000

Multiply both sides by 3/160

t^3/2 = 23000* 3/160

t^3/2 = 69000/160

t^3/2 = 431.25

t^(3/2 * 2/3) = 431.25^2/3

t = 57.080277

t = 57 days (approx.)

6 0
2 years ago
the sum of two numbers is zero. when 15 times the smaller numbers is added to 10 times the larger, the result is 1. find the two
EleoNora [17]

We have two numbers say a, b. And a system of equations.

a+b=0\wedge\dfrac{a+b}{15}+10(a+b)=1

It looks a bit intimidating but it's actually very easy.

Instead of term a + b in the second equation we can say it's zero because the first equation describes a + b as being equal to 0.

So,

\dfrac{0}{15}+10\cdot0=1\Longrightarrow 0+0=1

The above equation is not true therefore numbers a and b do not exists in the real number domain.

a,b\notin\mathbb{R}

No solution.

Hope this helps.

7 0
3 years ago
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