All categories

3 years ago

Please simplify 5(x-1)

Mathematics

2 answers:

vova2212 [387]3 years ago

7 0

Answer:

5x-5

Step-by-step explanation:

Just use distribuative property

Snowcat [4.5K]3 years ago

6 0

5x-5 is the correct answer

You might be interested in

What's the answer????

lara [203]

Answer:

Graph B

This is because of the vertical line test. Say you were to draw a vertical line that stretches through the whole graph. If this line you draw passes through more than two points of the same line/function/whatever b is, it is not a function.

5 0

3 years ago

Find the slope between two points ( -2,4) 3,-6)

Ksivusya [100]

Answer:

-1/2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Is the relation a function?

Margaret [11]

No; a domain value has two range values.

x = -2 then y = 1 and 2

they would form a vertical line, which tells us that it's not a function

8 0

4 years ago

To rent a certain meeting room, a college charges a reservation fee of $49 and an additional fee of $7.80 per hour. the math clu

yulyashka [42]

The math club could rent the room for up to 8 hours. I have also attached a picture of the work in case you need it.

4 0

3 years ago

Read 2 more answers

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago