For 25 tickets total cost of option one and option two to be the same.
Step-by-step explanation:
Let us assume the total number of rides = m
for which BOTH options cost same.
Case: 1
The cost of entry fee = $5
The cost per ride = $0.65
So, the cost of m rides = m x ( Cost of 1 ride )
= m x ($0.65 ) = 0.65 m
Cost of purchasing m tickets in first ride = Entry Fee + Per ticket cost
= 5 +0.65 m ..... (1)
Case: 2
The cost of entry fee = $10
The cost per ride = $0.45
So, the cost of m rides = m x ( Cost of 1 ride )
= m x ($0.45 ) = 0.45 m
Cost of purchasing m tickets in second ride = Entry Fee + Per ticket cost
= 10 +0.45 m ..... (2)
Now, equating (1) and (2), we get:
5 +0.65 m = 10 +0.45 m
or, 0.20 m = 5
or, m = 5/0.20 = 25
or, m = 25
Hence, for 25 tickets total cost of option one and option two to be the same.
