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lesya692 [45]
3 years ago
14

Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

None!

Step-by-step explanation:

Two lines are perpendicular when the product of their slopes equals -1.

The general equation of a line is:

y = m(x-x0) + y0. Where "m" represents the slope and (x0, y0) a point on the line.

Then, we find the slope of each equation:

a) y + 2 = –3(x – 4)   -> m=-3

b) y − 5 = 3(x + 11)  -> m=3

c) y = -3x  -> m= -3

d) y = x – 2  -> m=1

e) 3x + y = 7 -> m= -3

And the slope of the line y – 1 = (x+2) is m=1.

So, multiplying the slopes:

a) -3 * 1 = -3

b) 3 * 1 = 3

c) -3 * 1 = -3

d) 1 * 1 = 1

e) -3 * 1 = -3

None of the lines are perpendicular to  the line y – 1 = (x+2)

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The length of a rectangle is 3 meter shorter than3 times its width.Find the length and width if the perimeter is 210 meters
Shkiper50 [21]

Answer:

length = 78 m , width = 27 m

Step-by-step explanation:

let w represent width then length l = 3w - 3

the perimeter (P) is calculated as

P = 2l + 2w = 210 , substitute values

2(3w - 3) + 2w = 210 ← distribute parenthesis and simplify left side

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Then length = 78 m and width = 27 m

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Answer:

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Step-by-step explanation:

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2 years ago
From the diagram below, if the sides AD = 3 and DC = 27, and BD = X + 3, find x.
Colt1911 [192]

Given:

• AD = 3

,

• DC = 27

,

• BD = x + 3

Let's solve for x.

To solve for x, apply the altitude formula:

\frac{AD}{BD}=\frac{BD}{DC}

Where BD is the altitude.

Cross multiply:

BD^2=AD*DC

Plug in the values and solve for x:

\begin{gathered} (x+3)^2=3*27 \\  \\ (x+3)^2=81 \end{gathered}

Take the square root of both sides:

\begin{gathered} \sqrt{(x+3)^2}=\sqrt{81} \\  \\ x+3=9 \\  \\ \text{ Subtract 3 from both sides:} \\ x+3-3=9-3 \\  \\ x=6 \end{gathered}

Therefore, the value of x is 6 .

ANSWER:

d. 6

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