The estimated answer to a multiplication problem is 800,000. Which of the following expressions could result in this answer? Exp
1 answer:
Answer:
8,146 x 121
Step-by-step explanation:
This is a problem in which you need to measure your understading of "orders of magnitude."
If the estimated answer is that means that we are looking at a multiplication in the "order of"
You need to look at the "orders of magnitude" of the things you're multiplying. In the first case, we have that would be "of the order of"
times
. So the whole multiplication would "of the order of"
or near
The correct answer, 8,146 x 121, is because it's "of the order of" times
and the gives us the
we need.
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Answer:
d.
Step-by-step explanation:
To convert a root to a fraction in the exponent, remember this rule:
The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.
In this question, the index is 4.
The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.
To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, = 2.
For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.
Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by .
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.
b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.
c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.