Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
Let us assume the number of movies for ehich the cost of both companies becomes the same = x
Then
55 + 4x = 110
4x = 110 - 55
4x = 55
x = 55/4
= 13.75
So
The number <span>number of movies for which the cost of Carl's cable company is less than the cost of Teleview = 13.
I hope the procedure is clear enough for you to understand and this is the answer that you were actually looking for.</span>
Answer:
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Step-by-step explanation:
