Answer:(a=5,b=3)
7a-3b = 26--------(1)
a + 2b =11---------(2)
on mutlplying by7 in eq 2
= 7a+14b=77-------(3)
from eq(1) and (3) (on substracting)
7a+14b=77
7a-3b=26
________
=-17b=51
b=51/17
b=3
on putting value of b in eq 1
7a-3b = 26
=7a-9=26
7a=35
a=5
Step-by-step explanation:
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The answer is (2,0)
Explanation
So I’m gonna use substitution to help me solve this problem. I’m gonna solve for x.
X-y=2
+y. +y
X= y + 2
Now that we have solved for x we are going to plug it into the first equation!
Shown like this
Y+2 - 10y = 2
Then we solve it as a normal problem
So first we combine light terms
-9y+2=2
Then we isolate the variable
-9y+2=2
-2. -2
-9y = 0
Then we divide by -9 on both sides
-9y /-9 = 0 / -9
Y = 0
Now that we solved for y we plug it into one the equations to get the x value!
X - 0 = 2
X=2
The solution is (2,0)
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Answer:
y = ix + 6i + 4
Step-by-step explanation:
Since the line has undefined slope or indefinite slope we connote that the slope is (i)
Slope(m) of straight line = change in y ÷ change in x
Taking another point (x,y) on the line:
i = 
i = 
Cross multiplying gives;
y - 4 = ix + 6i
y = ix + 6i + 4
X = 59, y = 44
2x + 18 + x - 15 = 180
3x + 3 = 180
3x = 177
x = 59
x - 15 = y
59 - 15 = y
44 = y
The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
In the question ,
it is given that
the time taken to vacate the stadium = 20 minutes
number of exits = 25 exits
capacity of the stadium = 25000 spectators .
given that ,
time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .
time taken ∝ number of spectators ∝ 1/number of exits .
to remove the proportionality sign , we write the constant
time taken = k * (number of spectators)/(number of exits) .
20 = k * 25000/25
20 = k * 1000
k = 20/1000
k = 2/100
k = 1/50 = 0.02
So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula
time taken = (0.02)*(21000/15)
= 0.02*1400
= 28
Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
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