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chubhunter [2.5K]
3 years ago
9

Caleb is growing a plant in science class. The plant grows 0.4 centimeters each week. How much will the plant grow is 3 weeks?

Mathematics
2 answers:
den301095 [7]3 years ago
8 0

Answer:

1.2 centimeters.

Step-by-step explanation:

If the plant grows .4 centimeters per week, you can multiply that number by three. The resulting value is the plant's total growth over three weeks.

Grace [21]3 years ago
7 0
It’s is 1.2 centimeters
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Find the area of the figure below
sergiy2304 [10]

Answer:

27

Step-by-step explanation:

break shape into two parts

rectangle - 4*3=12

triangle 6*5/2 = 15

add rect and triangle tgt - 12+15=27

6 0
2 years ago
Bob cycles 5.4 km every morning.how many feet are in 5.4 km, given that 1 mile=1.609 km and 1 mile=5,280 feet?
creativ13 [48]

Answer:

17,720 ft

Step-by-step explanation:

5.4 km * (1 mile)/(1.609 km) * (5280 ft)/(1 mile) = 17,720 ft

5 0
3 years ago
Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
WITCHER [35]

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0
2 years ago
If triangle ABC is reflected over the y‐axis, reflected over the x‐axis, and rotated 180 degrees, where will point A' lie?
Ronch [10]

Given that ABC is a triangle and is reflected over the y - axis, reflected over the x - axis and rotated 180°

We need to determine the coordinates of the point A'

<u>Reflection over the y - axis:</u>

The coordinates of the point A is (-2,1)

The transformation rule to reflect across the y - axis is (x,y)\rightarrow (-x,y)

Substituting the point (-2,1) in the rule, we get;

(-2,1)\rightarrow (2,1)

Thus, the coordinates of the point A after reflection over the y - axis is (2,1)

<u>Reflection over the x - axis:</u>

The transformation rule to reflect across the x - axis is (x,y)\rightarrow (x,-y)

Substituting the point (2,1) in the rule, we get;

(2,1)\rightarrow (2,-1)

Thus, the coordinates of the point A after reflection over the x - axis is (2,-1)

<u>Rotation about 180°:</u>

The transformation rule to rotate about 180° is (x,y)\rightarrow (-x,-y)

Substituting the point (2,-1) in the rule, we get;

(2,-1)\rightarrow (-2,1)

Thus, the coordinates of the point A after the rotation about 180° is (-2,1)

Therefore, the coordinates of the point A' is (-2,1)

Hence, Option B is the correct answer.

7 0
3 years ago
What is the equation of a line that passes through (-6, 2) and has a slope of `-(1)/(2)` ?
o-na [289]
This answer would be d
8 0
3 years ago
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