Estimate the midpoint of the points (6.1, 3.9) and (4.2, 8.1)

How can you determine if a relation is a function?

Montano1993 [528]

Answer:

cause none of the x's will repeat

Step-by-step explanation:

4 0

3 years ago

Write the standard form of the line that contains a slope of -1/2 and y-intercept of 1. Include your work in your final answer.

NemiM [27]

The slope intercept form would be y= -1/2x + 1 and to get it into standard form all you have to do is move the -1/2 x to the other side, making it 1/2x + y = 1

5 0

3 years ago

Brad runs a lap every 5 minutes and Ty runs a lap every 4 minutes. If they started at the same time, when will they get to the b

olganol [36]

20 minutes. On brads 4th run and Ty’s 5th run they will be at the beginning at the same time.

5 0

3 years ago

For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger

11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let X = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = $p=\frac{1}{120}$ .

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...$

In this case we need to compute the probability of 1 or more than 1 catastrophes in n missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}$

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166$

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410$

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803$

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419$

6 0

3 years ago

The manufacturing cost of a cell phone was $136. Sellers first marked up the cost by 25 percent. Sales were poor, so sellers dec

neonofarm [45]

Answer: Old selling price is $170 and new selling price is $159.12

Step-by-step explanation:

Given Cost Price , CP=$136

For old selling price

Selling Price(SP) = Cost Price(CP) + Markup Value(MV)

Now MV= $MV=\frac{CP\times 25}{100}=\$ \frac{136\times 25}{100}=\$ 34$

=>SP = $136+$34=$170

Thus old selling price is $170

For new selling price

New Markup Value(NMV) = $\frac{CP\times 17}{100}=\$ \frac{136\times 17}{100}=\$ 23.12$

=>New Selling Price , NSP= $136+$23.12=$159.12

Thus new selling price is $159.12

8 0

3 years ago

Read 2 more answers