3 years ago

Estimate the midpoint of the points (6.1, 3.9) and (4.2, 8.1)

Mathematics

1 answer:

nlexa [21]3 years ago

8 0

Answer:

1.9, 4.9

Step-by-step explanation:

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Answer:

d) 0.0132

Step-by-step explanation:

In a sample of size n, with proportion p, the standard error of the proportion is:

$SE_{p} = \sqrt{\frac{p(1-p)}{n}}$

In this problem, we have that:

$p = 0.26, n = 1100$

$SE_{p} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.26*0.74}{1100}} = 0.0132$

So the correct answer is:

d) 0.0132

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4 years ago

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Answer:

(-3 1/3, -1 1/3) Quadrant lll

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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