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Volgvan
3 years ago
5

The function f(x) = 95 + 32 converts temperatures from x degrees in Celsius

Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0

Complete question is;

The function f(x) = (9/5)x + 32 converts temperatures from x degrees in Celsius

to y degree in Fahrenheit. The function g(x) = (5/9)(x − 32) converts temperatures from x degrees in Fahrenheit to y degrees in Celsius.

a. Find (f o g) (x)

b. (g o f) (x)

Answer:

A) x

B) x

Step-by-step explanation:

A) f(x) = (9/5)x + 32

g(x) = (5/9)(x − 32)

Thus;

(f o g) (x) = (9/5)(g(x)) + 32

This gives;

(9/5)((5/9)(x − 32)) + 32 = x - 32 + 32 = x

B) (g o f) (x) = (5/9)((f(x)) − 32)

This gives;

(5/9)((9/5)x + 32 - 32) = x

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Number of Certified Organic Farms in the United States, 2001–2008
Vinil7 [7]

Answer:

ŷ = 739.49X + 4876.43

y = 6755.98 - 388.24x + 125.30x²

y = 5428.98(1.09)^x

B.)

Linear:

ŷ = 739.49(9) + 4876.43

y = 11531.8

Year 2010 ; x = 10

y = 739.49(10) + 4876.43

y = 12271.3

Year 2011 ; x = 11

y = 739.49(11) + 4876.43

y = 13010.8

Quadratic :

Year 2009 ; x = 9

y = 6755.98 - 388.24(9) + 125.30(9^2)

y = 13411.1

Year 2010 ; x = 10

y = 6755.98 - 388.24(10) + 125.30(10^2)

y = 15403.6

Year 2011 ; x = 11

y = 6755.98 - 388.24(11) + 125.30(11^2)

y = 17646.6

Exponential:

Year 2009 ; x = 9

y = 5428.98(1.09)^9

y = 11791.2

Year 2010 ; x = 10

y = 5428.98(1.09)^10

y = 12852.4

Year 2011 ; x = 11

y = 5428.98(1.09)^11

y = 14009.1

Step-by-step explanation:

X :

1

2

3

4

5

6

7

8

Y:

6231

6574

7237

7211

7701

8581

10302

11796

Using the online linear regression calculator :

The linear trend :

ŷ = 739.49X + 4876.43

Where x = year

With 2006 representing 1 ; and so on

Slope = m = 739.49

Intercept (c) = 4876.43

y = predicted variable

The quadratic model:

General form:

y = A + Bx + Cx²

y = 6755.98 - 388.24x + 125.30x²

The exponential model:

y = AB^x

y = 5428.98(1.09)^x

B.) Next three years :

Year 2009 ; x = 9

Year 2010 ; x = 10

Year 2011 ; x = 11

Linear:

ŷ = 739.49(9) + 4876.43

y = 11531.8

Year 2010 ; x = 10

y = 739.49(10) + 4876.43

y = 12271.3

Year 2011 ; x = 11

y = 739.49(11) + 4876.43

y = 13010.8

Quadratic :

Year 2009 ; x = 9

y = 6755.98 - 388.24(9) + 125.30(9^2)

y = 13411.1

Year 2010 ; x = 10

y = 6755.98 - 388.24(10) + 125.30(10^2)

y = 15403.6

Year 2011 ; x = 11

y = 6755.98 - 388.24(11) + 125.30(11^2)

y = 17646.6

Exponential:

Year 2009 ; x = 9

y = 5428.98(1.09)^9

y = 11791.2

Year 2010 ; x = 10

y = 5428.98(1.09)^10

y = 12852.4

Year 2011 ; x = 11

y = 5428.98(1.09)^11

y = 14009.1

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Answer:

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r = interest rate  (1% = 0.01)

n = number of times interest applied per time period  (360)

t = number of time periods elapsed (36 months = 3 years)

F = 2850(1 + \frac{0.01}{360})^{360*3}

F = 2850(1.030454105)

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Answer:

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Step-by-step explanation:

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