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Diano4ka-milaya [45]
3 years ago
15

On a certain hot​ summer's day,

Mathematics
1 answer:
svp [43]3 years ago
5 0
524 kids and 262 adults. In total there is 786 people
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Question 3 (Multiple Choice Worth 6 points)
Alik [6]

Answer:

negative 9 plus or minus the square root of 17 divided by 8

Step-by-step explanation:

move all terms to one side

4x^2 + 9x + 4= 0

Use the quadratic formula

and you get  negative 9 plus or minus the square root of 17 divided by 8

4 0
3 years ago
[-10 +(-3)]-[6+(-9)] how do you solve this question
victus00 [196]
You calculate
<span>[-10 +(-3)]-[6+(-9)]</span>
=[-10-3]-[6-9]
=-13-[-3]
=-13+3
= -10
5 0
3 years ago
I really need help!!!!!!
Citrus2011 [14]

We know that, In a Right Angled Triangle :

✿ (Hypotenuse)² = (First Leg)² + (Second Leg)²

From the Diagram :

✿ Hypotenuse = x

✿ First Leg \bf{= 2\sqrt{3}}

✿ Second Leg \bf{= \sqrt{6}}

\bf{\implies x^2 = (2\sqrt{3})^2 + (\sqrt{6})^2}

\bf{\implies x^2 = 12 + 6}

\bf{\implies x^2 = 18}

\bf{\implies x = 3\sqrt{2}}

3 0
4 years ago
NEED HELP ASAP, WILL GIVE BRAINLIEST
Stella [2.4K]

Given:

The equation of circle is

(x+3)^2+y^2=9

To find:

The polar form of given circle.

Solution:

We have,

(x+3)^2+y^2=9

x^2+2(x)(3)+(3)^2+y^2=9        [\because (a+b)^2=a^2+2ab+b^2]

(x^2+y^2)+6x+9=9

Subtracting 9 from both sides, we get

(x^2+y^2)+6x=0

We know that, x^2+y^2=r^2 and x=r\cos \theta.

r^2+6(r\cos \theta)=0

r(r+6\cos \theta)=0

r=0 and r+6\cos \theta=0

We know that, r is radius it cannot be 0. So,

r+6\cos \theta=0

r=-6\cos \theta

Therefore, the correct option is A.

4 0
3 years ago
Use the exponential regression equation y=1.63(1.84)x to estimate the value of y when x = 5.
Karo-lina-s [1.5K]
If my memory does not remember wrong you have to multiply 1.63x1.84=2.9992 after this you have y=2.9992x, you have to substituted the x for 5 y=2.9992(5) and that will equal to y=14.996 and rounded will be 15 hope I was able to help
5 0
3 years ago
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