The angles are the only constraint here that counts. If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees. Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle. If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.
The set of angles remains the same (50-50-80), but subject to the constraint mentioned above, the measure of any one of the sides has infinitely many possible values, so long as those values are positive.
A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to
. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A =
, B =
, and C =
.
A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to
.
Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.
Apply the <em>Cosine rule</em> to have:
=
+
- 2ab Cos C
So that;
=
+
- 2(6 * 6.5) Cos C
49 = 36 + 42.25 - 78Cos C
78 Cos C = 78.25 - 49
= 29.25
Cos C = 
= 0.375
C =
0.375
= 67.9757
C = 
Apply the <em>Sine rule</em> to determine the <u>value</u> of B,
= 
= 
SIn B = 
= 0.861
B =
0.861
= 59.43
B = 
Thus to determine the value of A, we have;
A + B + C = 
A +
+
= 
A =
- 127.4
= 52.6
A = 
Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A =
, B =
, and C =
.
For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814
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Answer:
m = 5, n = 2
Step-by-step explanation:

Answer:
$140
Step-by-step explanation:
i assume ur asking for how much is left over
250-35= 215
215-75= 140
$140 left
Answer:
B
Step-by-step explanation: