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Furkat [3]
3 years ago
7

PLEASE HELP- thank you :)

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer:

Option A

a + s = 1650  ;   3.5a + 2b = 4580

Step-by-step explanation:

a ------> number of adult tickets

s ------> number of student tickets

Total tickets = $ 1650

a +s = 1650

Cost of 'a' number of adult tickets = 3.50*a = 3.5a

Cost of 's' number of student tickets = 2*s = 2b

Revenue raise = $ 4580

3.5a + 2b = 4580

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Given two angles that measure 50 degrees and 80 degrees and side that measures 4 feet, how many triangles, if any, can be constr
kirza4 [7]
The angles are the only constraint here that counts.  If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees.  Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle.  If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.

The set of angles remains the same (50-50-80), but subject to the constraint mentioned above, the measure of any one of the sides has infinitely many possible values, so long as those values are positive.

3 0
3 years ago
A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes
Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}.

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

c^{2} = a^{2} + b^{2} - 2ab Cos C

So that;

7^{2} = 6^{2} + (6.5)^{2} - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

               = 29.25

Cos C = \frac{29.25}{78}

         = 0.375

C = Cos^{-1} 0.375

   = 67.9757

C = 68^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{6.5}{Sin B} = \frac{7}{Sin 68}

SIn B = \frac{6.5 *Sin 68}{7}

         = 0.861

B = Sin^{-1} 0.861

   = 59.43

B = 59.4^{o}

Thus to determine the value of A, we have;

A + B + C = 180^{o}

A + 59.4^{o} + 68^{o} = 180^{o}

A = 180^{o} - 127.4

  = 52.6

A = 52.6^{o}

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0
2 years ago
5m - 3n = 19; m - 6n = -7 /pls. help me solve this linear equation with two variables.
Allisa [31]

Answer:

m = 5, n = 2

Step-by-step explanation:

5m - 3 n = 19\\m - 6n = - 7 \ => m = -7 + 6n\\\\Substitute \ m  \ in \  5m - 3n = 19\\\\5(-7 + 6n) - 3n = 19\\-35 + 30n -3n = 19\\27n = 19 + 35 \\27n = 54 \\n = 2\\\\Substitute \ n = 2 \  in \  m = -7 + 6n\\\\m = -7 + (6 \times 2) = -7 + 12 = 5

5 0
3 years ago
ezekiel has $250 in his bank account he deposts $35 from his birthday and then buys clothes for school for $75
Semmy [17]

Answer:

$140

Step-by-step explanation:

i assume ur asking for how much is left over

250-35= 215

215-75= 140

$140 left

6 0
3 years ago
Which of the following lists is in order from least<br> to greatest?
Alex

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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