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Solve the following using Substitution method
2x – 5y = -13
3x + 4y = 15
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- To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

- Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

- Add 5y to both sides of the equation.


- Multiply
times 5y - 13.

- Substitute
for x in the other equation, 3x + 4y = 15.

- Multiply 3 times
.

- Add
to 4y.

- Add
to both sides of the equation.

- Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.
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- Substitute 3 for y in
. Because the resulting equation contains only one variable, you can solve for x directly.


- Add
to
by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.
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- The system is now solved. The value of x & y will be 1 & 3 respectively.
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The second one is correct. 66/300 = x/100
A cube has equal sides if they are 2÷ 1/2 each then L×W×H would be (2÷ 1/2)^3. To divide fractions we multiply the reciprocal.
2÷ 1/2 = 2/1 × 2/1 = 4
4×4 = 16×4= 64
answer is V = 64 inches cubed.
Answer: x<4
Step-by-step explanation: Let's solve your inequality step-by-step.
2x+1<9
Step 1: Subtract 1 from both sides.
2x+1−1<9−1
2x < 8
Step 2: Divide both sides by 2.
2x
/2 < 8
/2
x<4
Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet