The answer is 2 y= 2 so 3•2=6 6-4=2
The first one is a hexagon because it has 6 sides. The second figure is a heptagon because it has 7 sides.
I hope this helped!
Answer:
- m = (2-(-2))/(2-(-2)) = 4/4 = 1
- y +2 = 1(x +2)
Step-by-step explanation:
The point-slope form of the equation for a line with slope m through point (x1, y1) is ...
y -y1 = m(x -x1)
To find the slope of the line, find the ratio of the difference in y-values of the points to the difference in corresponding x-values. Here, the slope is ...
m = (2 -(-2))/(2 -(-2)) = 4/4 = 1 . . . work to compute slope
The problem statement tells you x1 = -2, y1 = -2. Putting the numbers in to the point-slope form gives ...
y -(-2) = 1(x -(-2))
y + 2 = x + 2 . . . equation form with m, (x1, y1) filled in
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The answer at the top leaves the slope shown as 1. We don't know how much simplification you are expected to do. Obviously, this <em>could</em> be simplified to y=x, but then the use of (-2, -2) for the point would not be obvious.
The volume of a rectangular prism is represented by the following equation:
Where the variables are for volume, width, height, and length, respectively.
We are given that the area of one end is 16 cm² (units have to be correct when solving these problems, so it's 16 cm², not 16 cm as described in the problem). We know that 
Using this knowledge, we can change the volume equation to our needs.
Note: We know that A is 16 since it's given
The volume is 208 cm³ (once again, incorrect units given). Insert this into the equation.
Divide both sides of the equation by 16.
The length is 13 cm.
Let me know if you need any clarifications, thanks!
9514 1404 393
Answer:
6. step 2; terms are improperly combined; it should be -61n-8=-8
7. no; point (2, 5) is not part of the solution in the left graph
Step-by-step explanation:
6. Step 2 should be ...
-61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n
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7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.
The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.
The point (2, 5) is not a solution to both inequalities.
