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yawa3891 [41]
3 years ago
10

Minh made a histogram showing the number of pets for each of his friends.

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer: the answer is C

Step-by-step explanation:

just answered it and it was correct :)

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Electric City is having a sale on compact discs. The regular price of $14.00 is decreased by 20%. What is the sale price?
rewona [7]
.20*14.00=2.80
14.00-2.80=11.20
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3 years ago
Danny made a mistake in the following problem.
mixas84 [53]
Line 3
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Adding and Subtracting Fractions Solve each problem. Write your answer as a mixed number(if possible) 1. 2 1/9 - 7/6= 2. 2/3 + 2
AleksandrR [38]
1) 1 1/6
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5 0
3 years ago
If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .
Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

  • FX(x)=P(X≤x)
  • FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

  • t(Y)≤v)
  • Fs(X)(u)=P(s(X)≤u)
  • Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0
3 years ago
I’m confused can someone get me the answer
siniylev [52]
Angle OPM and Angle LMK

When angles are corresponding, they're essentially on the same side. It's sort of hard to explain, so I'll attach a drawing. The one on the left with the check mark is a corresponding angle, and the one on the right with the X is a same-side angle. Essentially, corresponding angles are on the same side and are also equal, unlike same-side angles, which are supplementary angles.

Let me know if you don't understand my explanation.
-T.B.
4 0
3 years ago
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