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3 years ago

Minh made a histogram showing the number of pets for each of his friends.

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Answer: the answer is C

Step-by-step explanation:

just answered it and it was correct :)

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Teesha is in the French club. There are 29 students in the club. The French teacher will pick two students at random to guide vi

Makovka662 [10]

Probability of event A ( Tesha will not be picked as a guide ) :
P ( A ) = Number of ways it can happen / Total number of outcomes
P ( A ) = (29 - 2) / 29 = 27 / 29 ≈ 0.93
Answer:
The probability that Tesha will not be picked as a guide is 0.93 or 93 %.

5 0

3 years ago

Read 2 more answers

9. To make lemonade you need 30 ounces of water and

love history [14]

Answer:

Step-by-step explanation:

Hopefully this helps

6 0

3 years ago

A ramp is to be built beside the steps to the campus library. Find the angle of elevation of the 23-foot ramp, to the nearest

Usimov [2.4K]

Answer:

the angle of elevation is 12.56°

Step-by-step explanation:

the height of the ramp represents the opposite side and the length of the ramp the hypotenuse

we see that it has (angle, hypotenuse, opposite)

well to start we have to know the relationship between angles, legs and the hypotenuse

a: adjacent

o: opposite

h: hypotenuse

sin α = o/h

cos α= a/h

tan α = o/a

we choose the one with opposite and hypotenuse

sin α = o/h

sin α = 5ft / 23ft

sin α = 5/23

α = sin^-1 ( 5/23)

α = 12.56°

the angle of elevation is 12.56°

3 0

3 years ago

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$

Part b.

Consider V(3X + 2Y)

$\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}$

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

$3 X+2 Y \sim N(18,77)$

Thus,

$P(3 X+2 Y < 18)=0.5$

Part d.

Consider P(3X + 2Y < 28)

$Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}$

$\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}$

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0

2 years ago

Katelyn can complete 17 integer questions in one minute. Collin can also complete 17 integer questions in one minute. Which expr

BabaBlast [244]

Answer:

a: 17m + m

Step-by-step explanation:

Each one can answer 17 questions in 1 minute.

Each one can answer 17m questions in m minutes.

The total they can answer is 17m + 17m = 34m.

Every expression that is equal to 34m represents the amount they can both answer in the same number of minutes.

The expression we are looking for does not equal 34m.

a: 17m + m = 18m

b: 34m = 34m

c: 2(17m) = 34m

d: 17m + 17m = 34m

Only choice a does not equal 34m.

Answer: a: 17m + m

5 0

3 years ago