Please solve using the picture!!!

Broccoli costs $1.50 per pound at a store. How much money does 32 ounces of broccoli cost?

larisa [96]

There are 16 ounces in a pound.
16+16 = 32.
So 32 ounces is 2 pounds for a total $3.00.
Hope it helps!

8 0

4 years ago

Scientists are examining two different strains of a particular bacteria. The length of one strain of the bacteria measures 0.000

vesna_86 [32]

Scientists are examining two different strains of a particular bacteria. The length of one strain of the bacteria measures 0.000000368

mm, while the length of the second strain measures 0.000000064 mm. How much larger is the first strain than the second?

We can figure this out using scientific notation.

$0.000000368 - 0.000000064$

$= 3.04e-7$

Put 3.04e-7 in standard notation.

$0.00000304$

Put 0.00000304 back into scientific notation, instead with a multiply sign.

Move the dot back, making the number in between 1-10.

In this case, we would move it back 7 times.

$3.04$ · $10x^{-7}$

So the answer would be A.

3 0

3 years ago

What two numbers add to 2 and multiply to 0

kotykmax [81]

1 plus 1 equals 2 ,2 times 0 equals 0 .get it.

6 0

3 years ago

Read 2 more answers

The GRE is an entrance exam that most students are required to take upon entering graduate school. In 2014, the combined scores

zvonat [6]

82% of the scores will be between 286 and 322.

To find this answer, we need to find the z-scores for 286 and 322. This is done by diving the difference from the mean by the standard deviation.

(286 - 310) / 12 = -2 which gives a percent of 2.28%
(322 - 310) / 12 = 1 which gives a percent of 84.13%

Subtracting those 2 percents will tell us the difference between the two scores.

84.13 - 2.28 = 81.85% or about 82%

3 0

3 years ago

Read 2 more answers

Male players at the high school, college, and professional ranks use a regulation basketball that weighs 22.0 ounces with a stan

Whitepunk [10]

Answer:

The probability that a basketball will weigh between 21.4 and 23.8 ounces is 0.62465.

Step-by-step explanation:

We have all this information from the question:

The weights of the basketballs are approximately normally distributed.
The population mean, $\\ \mu$ , for basketball weights is 22.0 ounces, $\\ \mu = 22$ ounces.
The population standard deviation, $\\ \sigma$ , for basketball weights is 1.2 ounces, $\\ \sigma = 1.2$ ounces.

To answer this question:

First, we need to calculate the cumulative probability for $\\ x = 21.4$ ounces and $\\x = 23.8$ ounces.
Second, subtract both values to obtain the asked probability, that is the probability that [a basketball] will weigh between 21.4 and 23.8 ounces.

Important concepts to remember:

For this, it is crucial three concepts: the standard normal distribution, the standard normal table, and z-scores:

Roughly speaking, the standard normal distribution is a normal distribution for standardized values. We can obtain standardized values using the formula for z-scores:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

And these values represent the distance from the population mean in standard deviation units. When they are positive, these values are above the population mean, $\\ \mu$ . In case they are negative, they are below $\\ \mu$ .

We can obtain probabilities for any normally distributed data using the standard normal distribution. These values are tabulated into the standard normal table, available in Statistics books or on the Internet.

In general, these values are cumulative probabilities, that is, probabilities from $\\ -\infty$ to the value x in question (a raw value).

At this stage, we have enough information to solve the question.

Solving the question

Cumulative probability for $\\ P(X$ ounces.

Obtain the z-score, using [1], for $\\ x = 21.4$ ounces (without using units):

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{21.4 - 22}{1.2}$

$\\ z = \frac{-0.6}{1.2}$

$\\ z = -0.5$

That is, the raw score $\\ x = 21.4$ is 0.5 standard deviations below, $\\ z = -0.5$ , the population mean.

Getting $\\ P(X$ using the standard normal table.

Since $\\ P(X$ , we can consult the standard normal table, using $\\ z = -0.5$ as an entry (using its first column).

The first row of this table has a second digit in the decimal part for the value of z. In this case, this second digit is zero (or to be more precise, -0.00), because $\\ z = -0.50$ . With the intersection of these two values in the table, namely, -0.5 and -0.00, we finally obtain the cumulative probability, $\\ P(Z$ .

Thus, $\\ P(X$

Cumulative probability for $\\ P(X$ ounces.

We can follow the same steps as before:

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{23.8 - 22.0}{1.2}$

$\\ z = \frac{1.8}{1.2}$

$\\ z = 1.5$

$\\ P(X$ using the standard normal table (z =1.5, +0.00).

Therefore, $\\ P(X$

Then, to answer the probability that a basketball will weigh between 21.4 and 23.8 ounces, we subtract (as we mentioned before) both cumulative probabilities:

$\\ P(21.4 < X < 23.8) = P(-0.5 < Z < 1.5) = P(X$

Then, the probability that a basketball will weigh between 21.4 and 23.8 ounces is 0.62465.

We can see this probability represented by the shaded area in the below graph.

6 0

4 years ago