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2 years ago

I need extra help please, -7y^2-2y^2+y^3y-2y+5y^3-2y

Mathematics

1 answer:

joja [24]2 years ago

3 0

Answer:

How to solve your problem

−

-7y^{2}-2y^{2}+y^{3}y-2y+5y^{3}-2y

−7y2−2y2+y3y−2y+5y3−2y

Simplify

Combine exponents

−

-7y^{2}-2y^{2}+{\color{#c92786}{y^{3}y}}-2y+5y^{3}-2y

−7y2−2y2+y3y−2y+5y3−2y

−

-7y^{2}-2y^{2}+{\color{#c92786}{y^{4}}}-2y+5y^{3}-2y

−7y2−2y2+y4−2y+5y3−2y

Combine like terms

−

{\color{#c92786}{-7y^{2}}}{\color{#c92786}{-2y^{2}}}+y^{4}-2y+5y^{3}-2y

−7y2−2y2+y4−2y+5y3−2y

−

{\color{#c92786}{-9y^{2}}}+y^{4}-2y+5y^{3}-2y

−9y2+y4−2y+5y3−2y

Combine like terms

−

-9y^{2}+y^{4}{\color{#c92786}{-2y}}+5y^{3}{\color{#c92786}{-2y}}

−9y2+y4−2y+5y3−2y

−

-9y^{2}+y^{4}{\color{#c92786}{-4y}}+5y^{3}

−9y2+y4−4y+5y3

Rearrange terms

−

{\color{#c92786}{-9y^{2}+y^{4}-4y+5y^{3}}}

−9y2+y4−4y+5y3

−

{\color{#c92786}{y^{4}+5y^{3}-9y^{2}-4y}}

y4+5y3−9y2−4y

Solution

−

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Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)

xxMikexx [17]

Answer:

a) 5+13k where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

$8x \equiv 1 (mod 13) \text{ means } 8x-1=13k$ .

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

$8x \equiv 4 (mod 13)$

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

8 0

3 years ago

Read 2 more answers

Is point (2,1) on the the line represented by the equation x+2y=5

Sphinxa [80]

To check if this point lies on the line, plug in a 2 for x and a y for 1 and solve

x+2y=5
2+2(1)=5
4=5

Since this statement isn't true, then the point doesn't lie on the line

Hope this helps

6 0

3 years ago

Read 2 more answers

Need help with math question

mote1985 [20]

Answer:

(-7,4)

Step-by-step explanation:

goal: (y-k)^2=4p(x-h)

y^2-8y=4x+12 Rearranged and added 4x and 12 on both sides

y^2-8y+(-8/2)^2=4x+12+(-8/2)^2 complete square time (add same thing on both sides)

y^2-8y+(-4)^2=4x+12+(-4)^2 (simplify inside the squares)

(y-4)^2=4x+12+16 (now write the left hand side as a square)

(y-4)^2=4x+28

(y-4)^2=4(x+7) factored...

vertex is (-7,4)

4 0

3 years ago

Read 2 more answers

The measurement of a pressure valve starts at 36 psi and falls to 30 psi. What is the approximate percent decrease in the readin

lukranit [14]

Answer:the answer is a 17psi

Step-by-step explanation:

6 0

3 years ago

Which set of numbers has the largest variance?

trasher [3.6K]

Answer:

1) (1,3,4.7)

2) 6.8

3) the square root of the variance

4) has the same units as the underlying data

5) It has predictive power.

Step-by-step explanation:

From question one, it is possible to use an excel formula to calculate the variance of the set of numbers.

Now, to calculate the variance in an Excel sheet:

Make sure your data is in a single range of cells in Excel.

If your data represents the entire population, enter the formula as "=VAR. P(A1:A4). Since, we were given four variables

The variance for your data will be displayed in the cell.

i.e for set of numbers (7, 8, 9, 10)

variance = (VAR. P(A1:A4))

= 1.25

for set of numbers (1, 3, 4, 7)

variance = (VAR. P(A1:A4))

= 4.69

for set of numbers (4,2,1, 0)

variance = (VAR. P(A1:A4))

= 2.19

for set of numbers (1, 0, 2, 4)

variance = (VAR. P(A1:A4))

= 2.19

The set of numbers (1,3,4.7) indicates the largest variance from the foregoing.

2) What is the population variance of the following set of numbers: 3, 5, 8, 9, 10?

Using the same method explained in question 1, the population variance of the following set of numbers 3,5,8,9,10 can be calculated as:

For the set of numbers (3, 5, 8, 9, 10)

Variance = (VAR. P(A1:A5)) since it contains five sets.

= 6.8

3) Variance can be defined as the average of the squared differences from the Mean. Therefore, Standard deviation is the square root of the variance which is given as:

$S= \sqrt{\frac{E^N_i(x_i-x)}{N-1} }$

where;

s = sample standard deviation

N = the number of observations

$x_i$ = the observed values of a sample item.

x= the mean value of the observations

4) Standard deviation is useful because it has the same units as the underlying data

5) Of all the characteristics of Standard deviation when relating to finance, Standard deviation do not possess predictive power.

3 0

3 years ago