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ryzh [129]
3 years ago
12

C/2 + 5 = 1 what does C=?

Mathematics
2 answers:
svp [43]3 years ago
4 0
It’s -8 tell me if you need it explained for that thing
KatRina [158]3 years ago
3 0

Answer:

c = -8

Step-by-step explanation:

c/2 + 5 = 1

Move number 5 next one. Basicly one side it number one side are for letters. but the sings change. + tunrs to -  - turns to +. x turns into / / turns into x

c/2+ 5 -5 = 1 -5

Simplify

c/2 = -4

Multiply all terms by the same value to eliminate fraction denominators

c/2= -4

2 x c/2 = 2 ( -4 )

Simplify

2 x c/2 (cross out both of the twos)

c= 2 (-4)

c=-8

Hope this helps =)

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WHAT IS THE VALUE OF ANGLE N?
victus00 [196]

Answer:

32 degrees

Step-by-step explanation:

An inscribed angle is an angle with its vertex on the circle, formed by two intersecting chords. Angle N perfectly fits this description. An inscribed angle is equal to 1/2 of its intercepted arc (the arc opposite the angle). The arc opposite angle N is equal to 64 degrees, so angle N is equal to 1/2 of that, or 32 degrees

7 0
3 years ago
Does someone know this one please :)
GarryVolchara [31]
6/11(5/6)+2/11(5)
=5/11+10/11
=15/11
3 0
3 years ago
Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me​
Dmitry_Shevchenko [17]

Answer:

(see attachment for tree diagram)

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

<h3><u>Part (a)</u></h3>

\textsf{P(Head) and P(3)}=\sf \dfrac{1}{2} \times \dfrac{1}{6}=\dfrac{1}{12}

<h3><u>Part (b)</u></h3>

\textsf{P(Tail) and P(even)}=\sf \dfrac{1}{2} \times \dfrac{3}{6}=\dfrac{3}{12}=\dfrac{1}{4}

<h3><u>Part (c)</u></h3>

\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-\dfrac{1}{6}=\dfrac{5}{6}

\implies \textsf{P(Head) and P(not 6)}=\sf \dfrac{1}{2} \times \dfrac{5}{6}=\dfrac{5}{12}

<h3><u>Part (d)</u></h3>

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

\implies \textsf{P(Head) and P(7)}=\sf \dfrac{1}{2} \times 0=0

7 0
2 years ago
Please help me i need an answer
azamat
C. 4<=C<=12 

Hope that helps
5 0
3 years ago
A new online music service has a collection of 1,500 songs. It expects to triple the number of songs each year for the next few
Rzqust [24]

Answer: y = (3^(x-1))*1500

Step-by-step explanation:

We want the relationship

y = f(x)

where y is the number of songs, and x is the number of years.

We know that in the first year, x = 1, the site has 1,500 songs.

The next year, x = 2, the number of songs is tripled, then we will have:

1,500*3 = 4500 songs.

The next year, x = 3, we will have: 3*(3*1500) = (3^2)*1500.

when x = 4, the number is tripled again:

3*(3^2)*1500 = (3^3)*1500

We already can see the pattern, for the year x, the site will have:

y = (3^(x-1))*1500 songs.

This is the equation we are looking for.

7 0
3 years ago
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