Answer:
C = 77°
Step-by-step explanation:
From the intercepted arc theorem, we can say that Angle ABC (angle B) is HALF of the arc intercepted (which is 110).
Hence, angle ABC = 55.
Now, looking at triangle ABC, we know that sum of 3 angles of a triangle is 180. We already know Angle A to be 48 and Angle B to be 55, thus Angle C is:
A + B + C = 180
48 + 55 + C = 180
103 + C = 180
C = 180 - 103
C = 77
Answer:
perpendicular line through a point on a line
Step-by-step explanation:
The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.
The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)
So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.
Segment GH is perpendicular to AB through point C (on AB).
x= hot dogs
y= soda
Total sold
1 x + 1 y = 87 .............1
2 x 0.50 y = 78.50 .............2
Eliminate y
multiply (1)by -0.50
Multiply (2) by 1.00
-0.50 x -0.50 y = -43.50
2 x + 0.50 y = 78.50
Add the two equations
1 x = 35.00
/ 1
x = 35.00
plug value of x in (1)
1 x + 1 y = 87
35 + y = 87
y = 87 -35
y = 52
y = 52.00
x= 35 hot dogs
y= 52 soda
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
