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3 years ago

Ok please help meeeeeeeeeeeeeeeee

Mathematics

1 answer:

valina [46]3 years ago

8 0

Answer:

Step-by-step explanation:

Volume of a cone is given by the formula,

V = $\frac{1}{3}\pi r^{2}h$

Here, r = Radius of the circular base of the cone

h = Height

By substituting values from the question,

V = $\frac{1}{3}\times \pi (\frac{6}{2})^2(3)$

V = 9π

V = 28.27 m³ [Nearest hundred]

If we have to round the answer to the nearest tenth, answer will be,

Volume = 28.3 m³

If we have have to round the answer to the whole number then the answer will be,

Volume = 28 m³

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Please help me, Identify each pair of angles named below as adjacent angles or vertical angles.

jarptica [38.1K]

Adjacent angles:

-ADB and BDC

-BDC and CDE

-CDE and EDF

-FDG and GDA

-GDA and ADB

Vertical angles:

-GDA and CDE

-FDE and ADB

-GDF and BDC

Hope this helps! :)

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3 years ago

The output is one more than six times the input. Answer in this form y=mx+b

stepladder [879]

Y= 6x + 1.
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3 years ago

A. 18 is 20 percent of what number? B. 15 is 25 percent of what number? C. 12 is 30 percent of what number? D. 24 is 40 percent

3241004551 [841]

Answer:

18=x*.20

15=x*.25

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Step-by-step explanation:

To solve for x on each, divide the number on the left of the equal side by the number x is being multiplied by. For example, 18/.20=x

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3 years ago

Read 2 more answers

Write a number story to fit this number sentence. 20- (3x6) =2

Anna [14]

Answer: Bonnie went to a meadow to pick flowers there was 20 flowers in one area and had decided to pick 18 of the flowers, how many flowers are left?

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3 years ago

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

6 0

3 years ago