All categories

2 years ago

.08 is 10 times as much as

Mathematics

1 answer:

Mazyrski [523]2 years ago

5 0

It is 10 times as much as .008

Do you see the pattern?

You might be interested in

Pls help mee I need help one this it's hard

vlada-n [284]

1 . 7/6 simplify it and you get the total of 1 1/6
2. 1
3. -2/3
4. 3/2 simplify it and you get 1 1/2

4 0

2 years ago

a spinner is divided into four equal sections labeled 1 to 4. What is the probability that the spinner will land on 2?

zalisa [80]

1 out of 4 would be the answer

8 0

3 years ago

natulia [17]

Answer: C) Angles A and J

Step-by-step explanation:

Corresponding angles are kind of angles that are in the same position, angles a and J are both right and top corner of the parallelogram.

3 0

2 years ago

A sinusoidal function whose period is 1/2 , maximum value is 10, and minimum value is −4 has a y-intercept of 3.

Elina [12.6K]

Answer:

brainly.com/question/10395117

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.

Step2247 [10]

After using the property of power, the expressions as a power of the number a is $(a^3)^{-2} = a^{-6}$ , $(a^{-1}\cdot a^{-2})^{-3} = a^{9}$ and $((a^2)^{-2})^2=a^{-8}$ .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is $(a^3)^{-2}$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

Simplifying the expression.

$(a^3)^{-2} = a^{3*(-2)}$

$(a^3)^{-2} = a^{-6}$

The second expression is $(a^{-1}\cdot a^{-2})^{-3}$

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}$

Using the property of sum of power $a^m\cdot a^n=a^{m+n}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{9}$

The third expression is $((a^2)^{-2})^2$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=((a^2)^{(-2)\times2})$

$((a^2)^{-2})^2=(a^2)^{-4}$

Again using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=a^{2\times(-4)}$

$((a^2)^{-2})^2=a^{-8}$

To learn more about property of power link is here

brainly.com/question/28747844

#SPJ1

7 0

11 months ago