Answer:
Step-by-step explanation:
Given
Probability of clearing exam in 1 st attempt=0.5
Probability of clearing exam in 2 nd attempt=0.7
Probability of clearing exam in 3 rd attempt=0.8
Probability that she passes the exam
(b)P(Pass qualification on 2nd try|passes qualification)
P(Pass qualification on 2nd try|passes qualification)
P(Pass qualification on 2nd try|passes qualification)
Answer:
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If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7
Given,
The average of x and y = 11
We know average = Sum of the terms / Number of terms
Then, the equation will become
x+y =11×2
x+y =22
Average of x, y and z = 5
x+y+z = 5×3
x+y+z =15
Substitute the value of x+y
22+z=15
z =15-22
x = -7
Hence, If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7
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