When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.
Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.
See the drawing attached below.
Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:
m<DIE + m<HID = 18
40 + m<HID = 180
m<HID = 140
Similarly:
m<BHC + m<CHI = 180
130 + m<CHI = 180
m<CHI = 50
Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:
m<DIE = m<GIH = 40
m<GIE = m<HID = 140
m<CHI = m<AHB = 50
m<BHC = m<AHI = 130
Answer:
Jackson ran 5/24 miles further than him
Step-by-step explanation:
7/8-2/3 = 21/24 - 16/24 = 5/24 miles or approx. 0.208 miles further than him
2(4z-9-11)=166-46
8z-18-22=120
8z-40=120
Add 40 from both side
8z-40+40=120+40
8z=160
Divided 8 from both side
8z/8=160/8
z=20. Hope it help!
Answer:
okay let's start
Step-by-step explanation:

Angles at right-angle add up to 90 degrees
The measure of acute angle Tryon Street forms with Barton Road is <em>33 degrees</em>
The angle is given as:
---- <em>Angle formed by Tryon Street with Olive Tree Lane. </em>
The measure of the acute angle formed by Tryon Street with Barton Road (B) is calculated using:
---- angle at right-angle
Make B the subject

Substitute 57 for A


Hence, the measure of acute angle is 33 degrees
Read more about acute angles at:
brainly.com/question/10334248