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Alja [10]
3 years ago
10

Question: write your quadratic equation y=x^2-6x+7 in vertex form.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

y=(x-3)^2-2

  1. find the h value using h=-b/2a
  2. plug in the value (3) into the equation to solve for k
  3. use the values to write the equation in vertex form which is y=a(x-h)^2+k
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3 years ago
Find the value of 4x-6 when x=3 and y=-2
Bas_tet [7]
Answer:
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Step by step explanation:

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Was this solution helpful?
8 0
2 years ago
What is the solution of the system ? <br> 2x+3y=4 <br> x-y=-3
fgiga [73]
Change the equation, x - y = -3, to isolate x or y and plug that new equation into the equation 2x + 3y = 4

I changed it to: x = y - 3
so 
2(y - 3) + 3y = 4
2y - 6 + 3y = 4
5y - 6 = 4
5y = 4 + 6
5y = 10
y = 10/5
y = 2

then you plug that 2 into the equation x = y - 3 to get the value of x

x = (2) - 3
x = -1

you can check this by plugging the x and y values into the equation 2x + 3y = 4

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4 = 4

hope this helps :)




6 0
3 years ago
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k0ka [10]

Answer:

Step-by-step explanation:

The entered points belong to an increasing, linear function.

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