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Alja [10]
3 years ago
10

Question: write your quadratic equation y=x^2-6x+7 in vertex form.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

y=(x-3)^2-2

  1. find the h value using h=-b/2a
  2. plug in the value (3) into the equation to solve for k
  3. use the values to write the equation in vertex form which is y=a(x-h)^2+k
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If you have the option of choosing a loan that will accumulate 4%/ a interest compounded semi-annually compared to a loan that w
alexira [117]

Answer:

4%/ a interest compounded semi-annually

Step-by-step explanation:

The option that gives the lower interest rate payment would be more appropriate. to determine this calculate the effective interest rate

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M = number of compounding

(1 + 0.04/2)^2 - 1 = 4.04%

(1 + 0.04/12)^12 - 1 = 4.07%

the choice should be 4%/ a interest compounded semi-annually

6 0
3 years ago
1. Jerry has a photo that is 7 inches wide and 5 inches high. He wants to enlarge it so that the new photo has a
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8 0
2 years ago
7 is greater than or equal to w, and - 1 is less than w
kari74 [83]
This written as an expression is 7 >= w > -1

Hope this helps!
8 0
2 years ago
Plz help I’m in algebra 2
chubhunter [2.5K]

Could you take another photo with you zoomed a lil bit more so I can answer it?

4 0
3 years ago
Which of the following are solutions to the equation below?
Natasha2012 [34]
Both A and C would be solutions to the equation.

In order to solve for this you must first get the equation equal to 0. 

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Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(2)(2) } }{2(2)}

\frac{-5 +/- \sqrt{9} }{4}

\frac{-5 +/- 3 }{4}

\frac{-5 + 3 }{4} or -1/2 for the first answer

\frac{-5 - 3 }{4} or -2 for the second answer

5 0
3 years ago
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