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3 years ago

Question: write your quadratic equation y=x^2-6x+7 in vertex form.

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

7 0

y=(x-3)^2-2

find the h value using h=-b/2a
plug in the value (3) into the equation to solve for k
use the values to write the equation in vertex form which is y=a(x-h)^2+k

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I think of a number I multiply it by 2,add 50 and my answer is 74 what was my number

alisha [4.7K]

74-50 is 24. 24/2 is 12. your number was 12.

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3 years ago

Read 2 more answers

In ΔQRS, the measure of ∠S=90°, SR = 7, QS = 24, and RQ = 25. What is the value of the tangent of ∠Q to the nearest hundredth?

TEA [102]

Answer:tanQ=

adjacent

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≈0.2917≈0.29

Step-by-step explanation:

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2 years ago

What is the distance between the points (5, 1) and (-3,-5)?

Reil [10]

Answer: THIRD OPTION.

Step-by-step explanation:

For this exercise you need to use the formula for calculate the distance between two points. This is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the following points:

$(5, 1)$ and $(-3,-5)$

You can identify that:

$x_2=-3\\x_1=5\\\\y_2=-5\\y_1=1$

Knowing these values, the next step is to substitute them into the equation for calculate the distance between two points and then evaluate.

Therefore, the distance between $(5, 1)$ and $(-3,-5)$ is:

$d=\sqrt{(-3-5)^2+(-5-1)^2}\\\\d=10$

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2 years ago

In the diagram, JK || GI. If the ratio of HJ to JG is 3 to 1, then what is the ratio of HK to KI?

Ket [755]

Don’t click that is a scam to get your cookies

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2 years ago

You are working in a small, student-run company that sends out merchandise with university branding to alumni around the world.

topjm [15]

Answer:

The answer is "0.142466".

Step-by-step explanation:

Using the p formula for the proportion of nonconforming units through the subgrouping which can vary in sizes:

$p =\frac{np}{n}\\\\$

$\bar{p}=\frac{\Sigma np}{\Sigma n}\\\\$

Defects $= \frac{5}{100} \times 50 \\\\$

$p = \frac{5}{100} \times \frac{50}{50}=0.05\\\\$

It calculates the controls limits through the p-chart that is:

$UCL_{p},LCL_{p}=\bar{p} \pm \sqrt{\frac{\bar{p}(1-\bar{p})}{\bar{n}}}\\\\$

So, the upper control limits:

$= 0.05 + 3 \times \sqrt{(\frac{0.05\times(1-0.05)}{50})} \\\\= 0.142466$

7 0

2 years ago