Answer:
honestly, the graph look totally fine...
If one ere pressed to find something to complain about it, one could suggest that you do not know if this was the starting price of the stock or the ending price of the stock each day?... One could also argue that to be a bit more meaningful you might want to know the range of prices during each day...
look up what is called a candle stick graph.. each day looks like a candlestick... the top is the highest value each the bottom the lowest, and there is a line in the candle that shows the closing price
Step-by-step explanation:
Answer:
13. 5 minutes
Step-by-step explanation:
This is a simple proportion problem. Make two fractions where one item is always on the top and the other on the bottom.
Now, cross multiply (multiply the two numbers diagonal from each other and divide the diagonal with the x value)
576 x 3 = 1, 728
1, 728 / 128 = 13.5
Answer: 1 1/2
Step-by-step explanation: So you have 9 pounds and you have to distribute it out between 6 bags, so 9 divided by 6 you get 1 1/2 and so 1 1/2 pounds of sand go into each small bag
Answer: same. ( 6 degree )
Step-by-step explanation:
According to the question, An angle that measures 6° is drawn on a piece of paper. As you are looking at the angle through a×6 magnifying glass, which means it magnifies by a factor of 6 indeed. The length and the width of the shape may magnify by factor of 6, but the degree measure of the angle will remain the same.
Even if it is magnified by a factor of 100, the measure of the angle you see on the paper when you look through the magnifying glass will remain the same.
Answer:
0.8 Not Outlier
1.1 Not Outlier
10.2 Not Outlier
10.9 Not Outlier
Solution:
Arranging the numbers in ascending order:
0.8 1.1 4.9 5.2 5.8 5.9 6.1 6.1 7.4 10.2 10.9
we can see that the median is 5.9.
We can find the first quartile Q1 by getting the median in the lower half of the data
0.8 1.1 4.9 5.2 5.8
that is, Q1 = 4.9
We can find the third quartile Q3 by getting the median for the upper half of the data
6.1 6.1 7.4 10.2 10.9
that is, Q3 = 7.4
We subtract Q1 from Q3 to find the interquartile range IQR.
IQR = Q3 - Q1 = 7.4 - 4.9 = 2.5
We can now calculate for the upper and lower limits:
upper limit = Q3 + 1.5*IQR = 7.4 + (1.5*2.5) = 11.15
lower limit = Q1 – 1.5*IQR = 0.8 - (1.5*2.5) = -2.95
There is no data point that lies above the upper limit and below the lower limit, therefore, there are no outliers in the data set.
