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prisoha [69]
3 years ago
12

I needddddd helpppp itsss dueeeeeeeeeee TODAY

Mathematics
2 answers:
frosja888 [35]3 years ago
8 0

Answer-

Term and constant (Or coefficient, Im not dat smart c: )

Explanation-

The x and z would be variables  

Nimfa-mama [501]3 years ago
5 0

Answer:

Term and Coefficcent

Step-by-step explanation:

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What is the Estimate 823 - 242
ser-zykov [4K]
800-200=600 is a good estimate
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4 years ago
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PLZ HELP!!! Which of the following does not represent a function?
alex41 [277]
It should be the 3rd one
A function can only have ONE answer
E.g. y = a (correct)
y = +/-a (incorrect)
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3 years ago
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4(n-1)+2 = -23 +7n
liubo4ka [24]

Answer:

<h2><em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em></h2>

Step-by-step explanation:

4(n-1)+2 = -23 +7n

=> 4n - 4 + 2 = - 23 + 7n

=> 23 - 4 + 2 = 7n - 4n

=> 21 = 3n

=  > n =  \frac{21}{3}

=> <em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

6 0
3 years ago
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
36. What is the solution to x+3 = -6?<br><br>HELP! answer if you can!​
Arlecino [84]

Answer:

x = -9

Step-by-step explanation:

subtract 3 from both sides

x = -9

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3 years ago
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